One possible answer could be that a chemical reaction has occurred.
Answer:
we count the number of the molecules on each side of the equation.
Answer:
c. Only certain energies are allowed for the electron in a hydrogen atom
Explanation:
Emission spectrum are produced when the excited electron in a atom release the energy in the form of photons to come to ground state. These photons are of different wavelengths depending on the excitation state of emitting electron or transition of electron. These electromagnetic radiation are observed through prism to produce the spectrum.
As the name indicates this spectrum is produced by emission of energy. Although the electron can be excited by different methods such as by heating but the key point is that electrons in hydrogen atom will emit the photons of same energy which they absorb and each electron can absorb only certain type of energy. So four lines were observed in the visible spectrum of hydrogen because only certain energies are observed for hydrogen atom.
Answer:
A precipitate will be produced
Explanation:
The Ksp of AgBr is:
AgBr(s) → Ag⁺ + Br⁻
5.0x10⁻¹³ = [Ag⁺] Br⁻]
<em>Where [] are the concentrations in equilibrium of each ion.</em>
<em />
And if Q is:
Q = [Ag⁺] Br⁻]
<em>Where the concentrations are actual concentrations of each ion</em>
<em />
We can say:
IF Q >= Ksp, a precipitate will be produced
IF Q < Ksp, no precipitate will be produced.
the molar concentrations are:
[AgNO₃] = [Ag⁺] = 0.002M * (50mL / 100mL) = 0.001M
<em>Because 50mL is the volume of the AgNO₃ solution and 100mL the volume of the mixture of both solutions.</em>
[NaBr] = [Br⁻] = 0.002M * (50mL / 100mL) = 0.001M
Q = [0.001M] * [0.001M]
Q = 1x10⁻⁶
As Q > Ksp,
<h3>A precipitate will be produced</h3>
