Answer:
Iron remains = 17.49 mg
Explanation:
Half life of iron -55 = 2.737 years (Source)
Where, k is rate constant
So,
The rate constant, k = 0.2533 year⁻¹
Time = 2.41 years
= 32.2 mg
Using integrated rate law for first order kinetics as:
Where,
is the concentration at time t
is the initial concentration
So,
<u>Iron remains = 17.49 mg</u>
Rust (Fe2O3. 4H2O) is formed when iron interacts slowly with oxygen and water. Mass of Fe in grams is 2.18 x 10⁴ g.
<h3>What is the explanation?</h3>There are 2 moles of Fe atoms in 1 mole of Fe2O3-4H2O. The number of moles of Fe atoms in 45.2 kg rust is shown below.
Moles of Fe = 195.01 mol Fe₂O₃.4H₂O ( )
Moles of Fe = 390.02 mol Fe
Multiply the calculated number of moles of iron, Fe, by its molar mass which is 55.85
Mass of Fe = 390.02 mol Fe ( )
Mass of Fe = 2.18 x 10⁴ g Fe
Avogadro's number (6.022 x 1023) of molecules (or formula units) make up one mole of a substance (ionic compound). The mass of 1 mole of a chemical is indicated by its molar mass. It provides you with the amount of grams per mole of a substance, to put it another way.
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