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cluponka [151]
3 years ago
9

Calculate the [oh] for 0.46 Hcl

Chemistry
1 answer:
Bad White [126]3 years ago
3 0

Answer:

2.17 e -14

Explanation:

A strong acid like HCl ionize 100 % in water so [H3O+] = 0.46 M

[OH-] = Kw /  [H3O+]

        =  1.0 e -14 / 0.46

         = 2.17 e -14

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Explain why lithium is a strong reducing agent, whereas fluorine is a strong oxidizing agent.
Tom [10]
Lithium is a good reducing agent because it is electropositive [it rapidly gains electrons]
fluorine is  good oxidizing agent electronegative [it loses electrons fastly]
3 0
3 years ago
2)
vodomira [7]

Answer:

Final volume 30.513 L.

Explanation:

According to general gas equation:

P₁V₁/T₁ = P₂V₂/T₂

Given data:

Initial volume = 17 L

Initial pressure = 2.3 atm

Initial temperature = 299 K

Final temperature = 350 K

Final volume = ?

Final pressure = 1.5 atm

Solution:

P₁V₁/T₁ = P₂V₂/T₂

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 2.3 atm × 17 L × 350 K / 299 K × 1.5 atm

V₂  =  13685 atm .L.  K  / 448.5 K . atm

V₂  = 30.513 L

6 0
3 years ago
Would nitrogen gas be a mineral if it has a chemical formula of n2?
STALIN [3.7K]

<u>Answer:</u>

Nitrogen gas be a mineral only, if it is in organic forms.

<u>Explanation:</u>

Most of the forms of organic nitrogen is not be taken by plants, with the exception in the form of small organic molecules. Also plants can promptly take the nitrogen  when it is in other forms like ammonia and nitrate.

The microorganisms  in the soil converts the organic forms of nitrogen to mineral form when they decompose organic matters and  also fresh plant residues. This type of process is called mineralisation.

6 0
3 years ago
A 1.00 g sample of a metal X (that is known to form X ions in solution) was added to 127.9 mL of 0.5000 M sulfuric acid. After a
Semenov [28]

<u>Answer:</u> The metal having molar mass equal to 26.95 g/mol is Aluminium

<u>Explanation:</u>

  • To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}     .....(1)

Molarity of NaOH solution = 0.5000 M

Volume of solution = 0.03340 L

Putting values in equation 1, we get:

0.5000M=\frac{\text{Moles of NaOH}}{0.03340L}\\\\\text{Moles of NaOH}=(0.5000mol/L\times 0.03340L)=0.01670mol

  • The chemical equation for the reaction of NaOH and sulfuric acid follows:

2NaOH+H_2SO_4\rightarrow Na_2SO_4+H_2O

By Stoichiometry of the reaction:

2 moles of NaOH reacts with 1 mole of sulfuric acid

So, 0.01670 moles of NaOH will react with = \frac{1}{2}\times 0.01670=0.00835mol of sulfuric acid

Excess moles of sulfuric acid = 0.00835 moles

  • Calculating the moles of sulfuric acid by using equation 1, we get:

Molarity of sulfuric acid solution = 0.5000 M

Volume of solution = 127.9 mL = 0.1279 L    (Conversion factor:  1 L = 1000 mL)

Putting values in equation 1, we get:

0.5000M=\frac{\text{Moles of }H_2SO_4}{0.1279L}\\\\\text{Moles of }H_2SO_4=(0.5000mol/L\times 0.1279L)=0.06395mol

Number of moles of sulfuric acid reacted = 0.06395 - 0.00835 = 0.0556 moles

  • The chemical equation for the reaction of metal (forming M^{3+} ion) and sulfuric acid follows:

2X+3H_2SO_4\rightarrow X_2(SO_4)_3+3H_2

By Stoichiometry of the reaction:

3 moles of sulfuric acid reacts with 2 moles of metal

So, 0.0556 moles of sulfuric acid will react with = \frac{2}{3}\times 0.0556=0.0371mol of metal

  • To calculate the molar mass of metal for given number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Mass of metal = 1.00 g

Moles of metal = 0.0371 moles

Putting values in above equation, we get:

0.0371mol=\frac{1.00g}{\text{Molar mass of metal}}\\\\\text{Molar mass of metal}=\frac{1.00g}{0.0371mol}=26.95g/mol

Hence, the metal having molar mass equal to 26.95 g/mol is Aluminium

6 0
3 years ago
Someone help it’s due today
Kitty [74]

Answer:

All elements are neutral

Explanation:

The plum pudding model of the atom indicated that all elements are neutral. The model was proposed by J.J Thomson after he conducted his experiment on the gas discharge tube.

From the experiment he discovered electrons which he called cathode rays.

Therefore, he suggested the plum pudding model of the atom.

The model describes negatively charge sphere surrounded by positive charges to balance them.

6 0
3 years ago
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