<span>arccos (cos pi/2)=?
</span>cos pi/2=0, arccos (0)=?, we know that cos pi/2=0, so cos^-1 (o)= Pi/2, but cos^-1 (o)=arccos (0), so arccos (cos pi/2)=Pi/2
Answer:
x = 3
Step-by-step explanation:
ΔABC is 45 45 90 right triangle
The ratio of leg: hypo = a : a√2
Given: hypo AC = 6√2; so AB = BC = 6
ΔBCD is 30 60 90 right triangle
The ratio of short leg : long leg : hypo = x : x√3 : 2x
Hypo. BC = 6 = 2 (3)
So short leg BD = x = 3
With
, we have

Since
, we can further write this as

It's a quadratic so the parent function will be

We can see that it has been shifted to the right 5 units, which gives us a new function

It has also been shifted up 9 units:

But it has also been flipped across the y-axis which makes this the final change we need to do:
yo i dont know the answer but i hope you have a good day