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Alecsey [184]
3 years ago
8

C) when two electrons occupy the bonding molecular orbital above, what type of bond results? explain.

Chemistry
2 answers:
WARRIOR [948]3 years ago
7 0
There are only two possible bonds when molecular orbitals combine with each other. It can either be sigma bond, or a pi bond. You can differentiate between them by looking at the way they bond together. Sigma bond are much stronger because the orbitals are superimposed on each other. On the other hand, pi bond are overlapped only sideways.
Brrunno [24]3 years ago
3 0

Two atomic orbitals can overlap in two ways depending on their phase relationship. Orbital phases are a direct consequence of the nature of waves like electrons. In graphical representations of orbitals, the orbital phases are represented by plus or minus signs (which have no connection with electric charges) or by incising a lobe. The phase sign itself has no physical meaning except when mixing orbitals to form molecular orbitals.

<h2>Further Explanation </h2>

Molecular orbital diagrams, or OM diagrams, are a qualitative descriptive tool that explains chemical bonds in molecules in terms of general molecular orbital theory and linear combinations of atomic orbitals (LCAO) in particular. The basic principle of these theories is that when atoms are bound to form molecules, a number of atomic orbitals combine to form the same number of molecular orbitals, even though electrons can be redistributed between orbitals. This tool is very suitable for simple diatomic molecules such as dihydrogen, dioxygen, and carbon monoxide but becomes more complex when discussing relatively simple polyatomic molecules, such as methane. OM diagrams can explain why some molecules exist and others don't. They can also predict the strength of bonds, as well as electronic transitions that can occur.

In MO theory molecular orbitals are formed by overlapping atomic orbitals. Because σ bonds have greater overlap than π bonds, σ, and σ * bonds and antibonding orbitals have greater energy separation (separation) from pemisahan and π * orbitals. The energy of atomic orbitals correlates with electronegativity because more electronegative atoms hold their electrons more tightly, reducing their energy. MO modeling only applies if atomic orbitals have comparable energy; When the energy is very different, the bonding mode becomes ionic. The second condition for overlapping atomic orbitals is that they have the same symmetry.

Learn more

molecular orbital brainly.com/question/4816397

Details

Grade:  College

Subject:  Chemistry

keywords: molecular, orbital.

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Molarity of 0.50 mol sugar in 270 mL of solution.
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<h3>Answer:</h3>

1.85 M

<h3>Explanation:</h3>

<u>We are given;</u>

  • Number of moles as 0.50 mol
  • Volume of the solution is 270 ml

But, 1000 mL = 1 L

  • Thus, volume of the solution is 0.27 L

We are required to calculate the molarity of the solution;

  • Molarity refers to the concentration of a solution in moles per liter.
  • It is calculated by dividing number of moles with the volume.

Molarity = Moles ÷ Volume

In this case;

Molarity = 0.50 moles ÷ 0.27 L

             = 1.85 Mol/L or 1.85 M

Therefore, molarity of the solution is 1.85 M

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Which of the following equations does not demonstrate the law of conservation of mass?
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The third option does not obey the law of conservation of mass.

Option 3.

Explanation:

The law of conservation of mass states that the sum of the masses of reactants should be equal to the sum of the masses of the products.

For example, if we consider the first option to verify if it obeys law of conservation of mass or not, 2 Na + Cl₂ → 2 NaCl

So one way to verify it is to find the mass of Na, then multiply it with 2, and then add this with 2 times of mass of chlorine. So this sum should be equal to the 2 times mass of NaCl. But it is somewhat lengthy.

Another way to easily determine this is to check if the elements are present equally in both sides. Such as, in reactant side and product side 2 atoms of Na is present . Similarly, the Cl atoms are also present in equal number in both reactant and product side. Thus this obeyed the law of conservation of mass.

Like this, if we see the second option, there also 1 atom of Na is present in reactant and product side and 2 molecules of H is present in reactant and product side, 1 oxygen is present in reactant and product side and 1 Cl is present in reactant and product side. So it also obeys the law of conservation of mass.

But in the third option, P₄ + 5 O₂→ 2 P₄O₁₀, here, there is 4 atoms of P in reactant side but in product side there is (4*2) = 8 atoms of P. Similarly, the number of atoms of oxygen in reactants and product side is also not same. So the third option does not obey the law of conservation of mass.

The fourth option also obeys the law of conservation of mass as the number of atoms of each element is same in both the product and reactant side.

Thus, the third option does not obey the law of conservation of mass.

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