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bazaltina [42]
4 years ago
3

Sketch the function Ex versus x for both positive and negative values of x. Remember that Ex is negative when E points in the ne

gative x direction.

Physics
1 answer:
Orlov [11]4 years ago
3 0

Answer:

Here is the complete question.

A charge of 3 μC is at the origin. Sketch the function E x versus x for both positive and negative values of x. (Remember that Ex is negative when E points in the negative x direction.)

The graph is sketched in the attachment.

Explanation:

Since our electric field Eₓ = q/4πε₀x² (electric field for a point charge)

where q = electric charge = 3μC and x = distance from the origin of the charge. 1/4πε₀= 9 × 10⁹ Nm²/C².

Substituting the values into Eₓ  = 3 × 10⁻⁶×9 × 10⁹ /x²= 0.027/x². We plot values of x on the x- axis ranging from -3 to 3 into the equation to give us the graph for Eₓ. Note that the sign of Eₓ changes when x crosses the origin because of the direction of the electric field due to the new position of the charge. The graph is in the attachment below. Note that as x tends to zero, Eₓ tends to infinity and x tends to infinity, Eₓ tends to zero.

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A 1.0 × 10^3 kg sports car is initially traveling at 15 m/s. The driver then applies the brakes for several seconds so that -25
algol13

Answer:

Ea = 112500[J]

Eb = 87500[J]

Explanation:

To solve this problem we must use the principle of energy conservation which tells us that the energy of a body plus the work done or applied by the body equals the final energy of a body.

This can be easily visualized by the following equation:

E_{A}+E_{friction}=E_{B}

Now we must define the energies at points A & B.

<u>For point A</u>

At point A we only have kinetic energy since it moves at 15 [m/s]

So the kinetic energy

E_{A}=\frac{1}{2}*m*v_{A}^{2}  \\E_{A}=\frac{1}{2} *1000*(15)^{2} \\E_{A}=112500[J]

The final kinetic energy can be calculated as follows:

112500-25000=E_{B}\\E_{B}=87500[J]

8 0
3 years ago
Which law describes the interactions between charged particles when they are not in contact?
natulia [17]
The answer would be the coulombs law.

7 0
3 years ago
Read 2 more answers
What would most likely happen if one of the runners bagan jogging in knee-deep water
Nesterboy [21]
Then they will most likely slow down unless they do high knees or something like that 
7 0
4 years ago
Force X has a magnitude of 1260 ​pounds, and Force Y has a magnitude of 1530 pounds. They act on a single point at an angle of 4
weeeeeb [17]

Answer:

Fe= 2579.68 P

α= 24.8°

Explanation:

Look at the attached graphic

we take the forces acting on the x-y plane and applied at the origin of coordinates

FX = 1260 P , horizontal (-x)

FY = 1530  P , forming 45° with positive x axis

x-y components FY

FYx= - 1530*cos(45)° = - 1081.87 P

FYy= -  1530*sin(45)° = - 1081.87 P

Calculation of the components of net force (Fn)

Fnx= FX + FYx

Fnx= -1260 P -1081.87 P

Fnx= -2341.87 P

Fny=FYy

Fny= -1081.87 P

Calculation of the components of equilibrant force (Fe)

the x-y components of the  equilibrant force are equal in magnitude but in the opposite direction to the net force components:

Fnx= -2341.87 P, then, Fex= +2341.87 P

Fny=  -1081.87 P P, then, Fex= +1081.87 P

Magnitude of the equilibrant (Fe)

F_{n} = \sqrt{(F_{nx})^{2} +(F_{ny})^{2}  }

F_{e} =\sqrt{(2341.87)^{2}+(1081.87)^{2}  }

Fe= 2579.68 P

Calculation of the direction of  equilibrant force (α)

\alpha =tan^{-1} (\frac{F_{ny} }{F_{nx} } )

\alpha =tan^{-1} (\frac{1081.87 }{2341.87} )

α= 24.8°

Look at the attached graphic

6 0
3 years ago
The weight of a 72.0 kg astronaut on the Moon, where g = 1.63 m/s2 is (5 points) Select one: a. 112 N b. 117 N c. 135 N d. 156 N
Hunter-Best [27]

Answer: The weight of a 72.0 kg astronaut on the Moon is 117.36 N.

Explanation:

Mass of the astronaut on the moon , m= 72 kg

Acceleration due to gravity on moon,g  = 1.63 m/s^2

According to Newton second law of motion: F = ma

This will changes to = Weight = mass × g

Weight=72 kg\times 1.63m/s^2=117.36 N

The weight of a 72.0 kg astronaut on the Moon is 117.36 N.

5 0
4 years ago
Read 2 more answers
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