Ask question

Ask question

All categories

3 years ago

15

When a beta minus decay occurs in an unstable nucleus, what happens to the atomic number of the nucleus?The atomic number increa

ses by 1.The atomic number decreases by 1.The atomic number remains constant.The atomic number increases by 2.The atomic number decreases by 2.

1 answer:

WITCHER [35]3 years ago

6 0

Answer:

The atomic number increases by 1.

Explanation:

The beta minus decay is a process in which a neutron decays into a proton, emitting an electron and an anti-neutrino:

$n \rightarrow p + e + \bar{\nu}$

If this process occurs inside an unstable nucleus, we notice that:

- a neutron is converted into a proton, therefore

- the number of neutrons decreases by 1 and the number of protons increases by 1

Keep in mind that the atomic number of a nucleus corresponds to the number of protons it contains: therefore, since this number increases by 1, then the atomic number increases by 1.

You might be interested in

The angle between the two force of magnitude 20N and 15N is 60 degrees (20N force being horizontal) determine the resultant in m

BARSIC [14]

A) The resultant force is 30.4 N at $25.3^{\circ}$

B) The resultant force is 18.7 N at $43.9^{\circ}$

Explanation:

A)

In order to find the resultant of the two forces, we must resolve each force along the x- and y- direction, and then add the components along each direction to find the components of the resultant.

The two forces are:

$F_1 = 20 N$ at $0^{\circ}$ above x-axis

$F_2 = 15 N$ at $60^{\circ}$ above y-axis

Resolving each force:

$F_{1x}=F_1 cos \theta = (20)(cos 0)=20 N\\F_{1y}=F_1 sin \theta =(20)(sin 0)=0 N$

$F_{2x}=F_2 cos \theta = (15)(cos 60)=7.5 N\\F_{2y}=F_2 sin \theta =(15)(sin 60)=13.0 N$

So, the components of the resultant are:

$F_x = F_{1x}+F_{2x}=20+7.5 = 27.5 N\\F_y = F_{1y}+F_{2y}=0+13.0=13.0 N$

And the magnitude of the resultant is:

$F=\sqrt{F_x^2+F_y^2}=\sqrt{27.5^2+13.0^2}=30.4 N$

And the direction is:

$\theta=tan^{-1}(\frac{F_y}{F_x})=tan^{-1}(\frac{13.0}{27.5})=25.3^{\circ}$

B)

In this case, the 15 N is applied in the opposite direction to the 20 N force. Therefore we need to re-calculate its components, keeping in mind that the angle of the 15 N force this time is

$\theta=180^{\circ}-60^{\circ}=120^{\circ}$

So we have:

$F_{2x}=F_2 cos \theta = (15)(cos 120)=-7.5 N\\F_{2y}=F_2 sin \theta =(15)(sin 120)=13.0 N$

So, the components of the resultant this time are:

$F_x = F_{1x}+F_{2x}=20-7.5 = 12.5 N\\F_y = F_{1y}+F_{2y}=0+13.0=13.0 N$

And the magnitude is:

$F=\sqrt{F_x^2+F_y^2}=\sqrt{13.5^2+13.0^2}=18.7 N$

And the direction is:

$\theta=tan^{-1}(\frac{F_y}{F_x})=tan^{-1}(\frac{13.0}{13.5})=43.9^{\circ}$

Learn more about vector addition:

brainly.com/question/4945130

brainly.com/question/5892298

#LearnwithBrainly

7 0

3 years ago

A 12.0-g rock is placed in a slingshot with a spring constant of 200 N/m. The rock is stretched back 0.500 m. After the slingsho

kaheart [24]

The maximum velocity of the rock is 64.55 m/s

Answer: Option B

<u>Explanation:</u>

The possessed energy by the objects while motion called kinetic energy. It is directly proportionate to mass and square of velocity. The stored energy in the system called potential energy and expressed as below,

$\text { potential energy }=\frac{1}{2} \times(\text { spring constant }) \times\left(\text { distance from equilibrium) }^{2}\right.$

$U=\frac{1}{2} \times k \times x^{2}$

U = spring’s potential energy in certain place

k = the spring constant, in N/m.

x = the spring’s distance is stretched or compressed away from equilibrium

Conservation of energy states energy neither created nor destroyed but change from one form to other. So, using this concept, equating both potential and kinetic energies equation we get,

$\frac{1}{2} \times m \times v^{2}=\frac{1}{2} \times k \times x^{2}$

Given:

m = 12 g = 0.012 kg

k = 200 N/m

x = 0.500 m

Substitute these values we get,

$\frac{1}{2} \times 0.012 \times v^{2}=\frac{1}{2} \times 200 \times(0.500)^{2}$

$v^{2}=\frac{200 \times 0.25}{0.012}=\frac{50}{0.012}=4166.66$

Taking square root, we get,

$v=64.55 \mathrm{m} / \mathrm{s}$

7 0

4 years ago

Graphene based nanoelectronic devices will...a.Be slower, more power consuming than silicon and much thicker.b.Be faster, less p

nalin [4]

Answer:

.b.Be faster, less power consuming than silicon and much thinner

Explanation:

Graphene has a <em>very high electrical conductivity</em> due to its pi orbitals overlap that enhance the carbon to carbon bonds. This means that a nanoelectronic devise that uses graphene will be faster and will consume less powe and it will be thinner because graphenes have a <em>size of 0.345Nm.</em>

I hope you find this information useful and interesting! Good luck!

4 0

4 years ago

A person walks 2.00 m east, then turns and goes 4.00 m west, then turns and goes back 1.00 m east.

bekas [8.4K]

Answer:

i got -1.00

Explanation:

7 0

3 years ago

Read 2 more answers

Which describes a relationship when calculating the energy of a photon? The energy of the photon is directly proportional to fre

victus00 [196]

Answer:

The energy of a photon is directly proportional to it's frequency

8 0

3 years ago