Two 5.0-kg carts collide on a one-dimensional air track. The total momentum of the carts was 4.9 kg m/s rightwards before the co
2 answers:
You might be interested in
Answer:
The frequency of the piano string is <em>1059 Hz</em>.
Explanation:
The frequency beat (fb), 2 beats/second, is the absolute difference between the frequency of the tuning fork (1056 Hz) and the frequency of the piano string.
As the piano string gets tightened, the frequency beat becomes 3 beats/second.
Therefore,
fb =
Answer:
1. v = 30 m/s
2. v = 5 m/s
3. f = 40 Hz
4. f = 400 Hz
5. f = 300 Hz
6. λ = 0.772 m
7. λ = 0.386 m
8. λ = 0.625 m
9. v = 100 m/s
10. v = 50 m/s
Explanation:
The relationship between frequency, wavelength, and speed of a wave is given by the following formula:
where,
v = speed of wave
f = frequency of wave
λ = wavelength
1.
f = 100 Hz
λ = 0.3 m
Therefore,
v = (100 Hz)(0.3 m)
<u>v = 30 m/s</u>
<u></u>
2.
f = 50 Hz
λ = 0.1 m
v = (50 Hz)(0.1 m)
<u>v = 5 m/s</u>
<u></u>
3.
v = 20 m/s
λ = 0.5 m
<u>f = 40 Hz</u>
<u></u>
4.
v = 80 m/s
λ = 0.2 m
<u>f = 400 Hz</u>
<u></u>
5.
v = 120 m/s
λ = 0.4 m
<u>f = 300 Hz</u>
<u></u>
6.
v = 340 m/s
f = 440 Hz
<u>λ = 0.772 m</u>
<u></u>
7.
v = 340 m/s
f = 880 Hz
<u>λ = 0.386 m</u>
<u></u>
<u></u>
8.
v = 250 m/s
f = 400 Hz
<u>λ = 0.625 m</u>
<u></u>
9.
f = 50 Hz
λ = 2 m
v = (50 Hz)(2 m)
<u>v = 100 m/s</u>
<u></u>
10.
f = 100 Hz
λ = 0.5 m
v = (100 Hz)(0.5 m)
<u>v = 50 m/s</u>
Answer:
The coefficient of friction is 0.38.
Explanation:
The free body diagram is drawn below.
Let be frictional force acting in the backward direction as shown. Let the coefficient of friction be
. Let
be the normal reaction force acting on the bag.
Given:
Mass of the bag is,
Force acting at ° is
Acceleration due to gravity is,
The force F can be resolved into its components as and
Therefore,
Now, as there is no acceleration in vertical direction, therefore,
Sum of upward forces = Sum of downward forces
Now, as the bag is moving at a constant speed, so acceleration in the horizontal direction is also zero as acceleration is the rate of change of velocity.
Therefore, backward force = forward force.
Now, frictional force is given as:
Therefore, the coefficient of friction is 0.38.
