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mash [69]
2 years ago
13

Assume an individual has no sodium in their intestinal tract. if this were the case the asorption of _____ would be most affecte

d
Physics
1 answer:
Natali5045456 [20]2 years ago
8 0

Assume an individual has no sodium in their intestinal tract. if this were the case the asorption of  <u> </u><u> galactose  </u> would be most affected.

<h3>Transport of d-galactose by the gastrointestinal tract :</h3>

Adult insects' gastrointestinal tract epithelium is where nutrients are absorbed because of the exoskeleton. The majority of physiological investigations have described the intestinal absorption of sugar as a diffusional mechanism, and no sugar transporter has been successfully cloned from an insect's digestive system to date. The current investigation makes a convincing case for the existence of a saturable galactose transport system in the gastric caeca of Locusta migratoria.

Galactose absorption is unaffected by changes in pH, the absence of K+, Cl, Mg2+, or Ca2+, either. However, facilitative transporter inhibitors like as phloretin, cytochalasin B, and theophylline reduce sugar uptake by about 50%. The presence of an mRNA coding for at least one equilibrative sugar transporter in the L. migratoria gastric caeca is further supported by the observation that Xenopus laevis oocytes microinjected with poly A+ RNA isolated from gastric caeca show sodium-independent galactose uptake that is three times higher than in non-injected oocytes.

Learn more about galactose here:

brainly.com/question/28167750

#SPJ4

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horsena [70]

Answer:

D.None of these

Explanation:

The derivation of acceleration formula:

Let us call the 5kg mass m_2 and the 4kg mass m_1. If the tension in the string is T then for the mass m_2

(1). T-m_2g=-m_2a <em>(the negative sign on the right side indicates that acceleration is downwards)</em>

And for the mass m_1

(2). T-m_1g =m_1a<em> (the acceleration is upwards, hence the positive sign)</em>

Solving for T in the 2nd equation we get:

T =m_1a+m_1g,

and putting this into the 1st equation we get:

m_1a+m_1g-m_2g=-m_2a\\\\m_1a+m_2a = m_2g-m_1g\\\\a(m_1+m_2)= (m_2-m_1)g

\boxed{a= \dfrac{(m_2-m_1)}{(m_1+m_2)} g}

Back to the question:

Using the formula for the acceleration we find

a= \dfrac{(5kg-4kg)}{(5kg+4kg)} g

a = \dfrac{g}{9},

which is the acceleration that none of the given choices offer. Also, the acceleration of the two blocks is the same, because if it weren't, the difference in the instantaneous velocities of the objects would cause the string to break. Therefore, these two reasons make us decide that none of the choices are correct.

7 0
3 years ago
It is necessary to determine the specific heat of an unknown object. The mass of the object is 201.0 g. It is determined experim
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temperature change = 10C

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we can rearrange this to make specific heat capacity the subject

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c =\frac{15}{2.01}
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