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mash [69]
2 years ago
13

Assume an individual has no sodium in their intestinal tract. if this were the case the asorption of _____ would be most affecte

d
Physics
1 answer:
Natali5045456 [20]2 years ago
8 0

Assume an individual has no sodium in their intestinal tract. if this were the case the asorption of  <u> </u><u> galactose  </u> would be most affected.

<h3>Transport of d-galactose by the gastrointestinal tract :</h3>

Adult insects' gastrointestinal tract epithelium is where nutrients are absorbed because of the exoskeleton. The majority of physiological investigations have described the intestinal absorption of sugar as a diffusional mechanism, and no sugar transporter has been successfully cloned from an insect's digestive system to date. The current investigation makes a convincing case for the existence of a saturable galactose transport system in the gastric caeca of Locusta migratoria.

Galactose absorption is unaffected by changes in pH, the absence of K+, Cl, Mg2+, or Ca2+, either. However, facilitative transporter inhibitors like as phloretin, cytochalasin B, and theophylline reduce sugar uptake by about 50%. The presence of an mRNA coding for at least one equilibrative sugar transporter in the L. migratoria gastric caeca is further supported by the observation that Xenopus laevis oocytes microinjected with poly A+ RNA isolated from gastric caeca show sodium-independent galactose uptake that is three times higher than in non-injected oocytes.

Learn more about galactose here:

brainly.com/question/28167750

#SPJ4

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__________ is the school of psychology that believes perception is more than the sum of its parts—it involves a whole pattern. A
diamong [38]

Answer:

(D. Gestalt psychology) , is the school of psychology that believes perception is more than the sum of its parts, it involves a whole pattern .

This type of school of psychology studied how all components of sensations are assembled into one's perception .

hope this helps :)

4 0
3 years ago
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Which of the following models shows how unpredictable electrons are?
Fantom [35]

D

The exact location of electrons in electron shells of atoms cannot be exactly ascertained. This is why VSPER atomic models represent the position of electrons (s, p, d, & f) using the probability of where they would most be expected to be found.

Explanation:

This is because merely observing electrons changes their behavior. Remember that to observe something one has to shine light on it so it bounces back to the eye. Due to the negligible mass of electrons, mere photons of light will change their direction of movement, spin or other behaviors/properties.

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7 0
3 years ago
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A block of mass 57.1 kg rests on a slope having an angle of elevation of 28.3°. If pushing downhill on the block with a force ju
stira [4]

Answer:

The coefficient is 0.90

Explanation:

Drawing a diagram makes thing easier, we will assume that the acceleration tends to zero because it start barely moving.

-F_s+mg*sin(\theta)+F=0\\F_s=57.1kg*9.8m/s^2*sin(28.3)+177N\\F_s=442N\\F_s=\µ*N\\N=m*g*cos(\theta)\\N=57.1*9.8*cos(28.3)=493N\\\\\µ=\frac{442N}{493N}=0.90

3 0
3 years ago
A gun shoots a bullet with a velocity of 500 m/s. The gun is aimed horizontally and fired from a height of 1.5 m. How far does t
MrMuchimi

The bullet travels a horizontal distance of 276.5 m

The bullet is shot forward with a horizontal velocity u_x. It takes a time <em>t</em> to fall a vertical distance <em>y</em> and at the same time travels a horizontal distance <em>x. </em>

The bullet's horizontal velocity remains constant since no force acts on the bullet in the horizontal direction.

The initial velocity of the bullet has no component in the vertical direction. As it falls through the vertical distance, it is accelerated due to the force of gravity.

Calculate the time taken for the bullet to fall through a vertical distance <em>y </em>using the equation,

y=u_yt+\frac{1}{2} gt^2

Substitute 0 m/s for u_y, 9.81 m/s²for <em>g</em> and 1.5 m for <em>y</em>.

y=u_yt+\frac{1}{2} gt^2\\ 1.5 m=(0m/s)t+\frac{1}{2} (9.81m/s^2)t^2\\ t=\sqrt{\frac{2(1.5m)}{9.81m/s^2} } =0.5530s

The horizontal distance traveled by the bullet is given by,

x=u_xt

Substitute 500 m/s for u_x and 0.5530s for t.

x=u_xt\\ =(500m/s)(0.5530s)\\ =276.5m

The bullet travels a distance of 276.5 m.


5 0
3 years ago
The speed of light is 3.00×108m/s. How long does it take for light to travel from Earth to the Moon and back again? Express your
bija089 [108]

Answer:

v = 3×10^8 m/s

s= 384,400 km= 3.84×10^8 m/s

t = ?

v = s/t = 2s/t

t = 2s/v

t = (2×3.84×10^8) ÷ 3×10^8

t = 2.56 seconds

Explanation:

Earth's moon is the brightest object in our

night sky and the closest celestial body. Its

presence and proximity play a huge role in

making life possible here on Earth. The moon's gravitational pull stabilizes Earth's wobble on its axis, leading to a stable climate.

The moon's orbit around Earth is elliptical. At perigee — its closest approach — the moon comes as close as 225,623 miles (363,104 kilometers). At apogee — the farthest away it gets — the moon is 252,088 miles (405,696

km) from Earth. On average, the distance fromEarth to the moon is about 238,855 miles (384,400 km). According to NASA , "That means 30 Earth-sized planets could fit in between Earth and the moon."

7 0
3 years ago
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