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mash [69]
2 years ago
13

Assume an individual has no sodium in their intestinal tract. if this were the case the asorption of _____ would be most affecte

d
Physics
1 answer:
Natali5045456 [20]2 years ago
8 0

Assume an individual has no sodium in their intestinal tract. if this were the case the asorption of  <u> </u><u> galactose  </u> would be most affected.

<h3>Transport of d-galactose by the gastrointestinal tract :</h3>

Adult insects' gastrointestinal tract epithelium is where nutrients are absorbed because of the exoskeleton. The majority of physiological investigations have described the intestinal absorption of sugar as a diffusional mechanism, and no sugar transporter has been successfully cloned from an insect's digestive system to date. The current investigation makes a convincing case for the existence of a saturable galactose transport system in the gastric caeca of Locusta migratoria.

Galactose absorption is unaffected by changes in pH, the absence of K+, Cl, Mg2+, or Ca2+, either. However, facilitative transporter inhibitors like as phloretin, cytochalasin B, and theophylline reduce sugar uptake by about 50%. The presence of an mRNA coding for at least one equilibrative sugar transporter in the L. migratoria gastric caeca is further supported by the observation that Xenopus laevis oocytes microinjected with poly A+ RNA isolated from gastric caeca show sodium-independent galactose uptake that is three times higher than in non-injected oocytes.

Learn more about galactose here:

brainly.com/question/28167750

#SPJ4

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Tom [10]
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Vt= 80V
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V1= 15Ω*2A= 30V
V2= 20Ω*2A= 40V
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4 0
3 years ago
What would be the answer for this and how?
Veronika [31]

Answer:

B. 6 cm

Explanation:

First, we calculate the spring constant of a single spring:

k = \frac{F}{\Delta x}\\

where,

k = spring constant of single spring = ?

F = Force Applied = 10 N

Δx = extension = 4 cm = 0.04 m

Therefore,

k = \frac{10\ N}{0.04\ m}\\k =  250\ N/m\\

Now, the equivalent resistance of two springs connected in parallel, as shown in the diagram, will be:

k_{eq} = k + k\\k_{eq} = 2k = 2(250\ N/m)\\k_{eq} = 500\ N/m\\

For a load of 30 N, applying Hooke's Law:

\Delta x = \frac{F}{k_{eq}}\\\\\Delta x = \frac{30\ N}{500\ N/m}\\\\\Delta x = 0.06\ m = 6\ cm\\

Hence, the correct option is:

<u>B. 6 cm</u>

7 0
3 years ago
En un momento dado , la nadadora de una prueba de natación de 100 m espalda está debajo de la cuerda falsa de salida. Indica a)
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Answer:

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Explanation:

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7 0
3 years ago
An ice skater has a moment of inertia of 5.0 kgm2 when her arms are outstretched. at this time she is spinning at 3.0 revolution
givi [52]
With arms outstretched,
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Assume that the same torque drives the rotational motion at a moment of inertia of 2.0 kg-m².
If u = new rotational speed (rad/s), then
T = 2u = 30π
u = 15π rad/s
   = (15π rad/s)*(1 rev/2π rad)
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Answer: 7.5  revolutions per second.

7 0
4 years ago
Which is an example of action and reaction forces?
Vlad [161]

Hey there!

the answer is

C. a tennis racket striking a tennis ball

Thank you

Best regards

           OFFICIALLYSAVAGE2003

7 0
4 years ago
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