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Shkiper50 [21]
3 years ago
9

What is the mechanical advantage of a machine that applies a force of 1000 N to an object when a force of 500 N is applied to th

e machine?
0.5
2
500
1500
Physics
2 answers:
Nimfa-mama [501]3 years ago
8 0

Answer:

2

Explanation:

sergij07 [2.7K]3 years ago
4 0
Effort out = 1000 N
Effort in = 500 N
Mechanical advantage = Effort out / Effort in
                                     = 1000/500 
                                     = 2
From the above deduction, we can conclude that the correct option among all the options that are given in the question is the second option. I hope that this is the answer that you were looking for and the answer has actually come to your desired help.
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An airplane takes off from Dallas Texas to fly to new york city traveling ne for 2,760 km the Same plane returns that day to Dal
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<h3>Answer</h3>

1104 km/hour

<h3>Explanation</h3>

Distance between Dallas Texas to New York = 2760 km

Time the plane took from Dallas to New York = 2 hours

Time the plane took from New York back to Dallas = 2.5 hours

Formula to use

<h3>distance = speed x time </h3>

Speed the plane took from Dallas to New York

2760 = 2 x speed

speed = 2760 / 2

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Speed the plane took from New York to Dallas (ROUND TRIP)

2760 = 2.5 x speed

speed = 2760 / 2.5

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3 years ago
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faust18 [17]

Answer:

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Explanation:

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3 years ago
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It has been suggested that rotating cylinders several miles in length and several miles in diameter be placed in space and used
stepladder [879]

Answer:

the required revolution per hour is 28.6849

Explanation:

Given the data in the question;

we know that the expression for the linear acceleration in terms of angular velocity is;

a_{c} = rω²

ω² = a_{c} / r

ω = √( a_{c} / r )

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ω is the angular velocity

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so, given that, diameter = 4.86 miles = 4.86 × 1609 = 7819.74 m

Radius r = Diameter / 2 = 7819.74 m / 2 = 3909.87 m

so we substitute

ω = √( 9.8 m/s² / 3909.87 m )

ω = √0.002506477 s²  

ω = 0.0500647 ≈ 0.05 rad/s  

we know that; 1 rad/s = 9.5493 revolution per minute

ω = 0.05 × 9.5493 RPM

ω = 0.478082 RPM  

1 rpm = 60 rph  

so  

ω = 0.478082 × 60

ω = 28.6849  revolutions per hour  

Therefore, the required revolution per hour is 28.6849

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