Answer:
They are equidistant from origin.
Step-by-step explanation:
Rectangle LMNO is rotated 90° clockwise around the origin to create rectangle L'M'N'O'. Which statement would best describe the relationship between points N and N'?
They are equidistant from origin.
They are midpoints of segment ON and segment O prime N prime.
They are equidistant from point O.
They are midpoints of segment LN and segment L prime N prime.
Answer: If a point with location N(x, y) is rotated 90° clockwise around the origin, the new coordinate N' is at (y, -x). The distance of the two points from the origin O(0, 0) can be calculated using:
Therefore ON = ON'. The points N and N'are equidistant from the orign
Answer:
A on edge
Step-by-step explanation:
I think you meant to add more to your question (posting the specific problem).
In general, one special right triangle is the <span>45°-45°-90° triangle, in which both legs are congruent and the hypotenuse = √2 * the length of the leg. if you happen to not have the length of the leg, the formula for finding the leg is: leg = hypotenuse / √2
Another special right triangle is the </span><span>30°-60°-90° triangle. With this kind of triangle the length of the hypotenuse is twice the length of the shorter leg. The length of the longer leg is √3 times the length of the shorter leg.
hypotenuse = 2 * shorter leg
longer leg = √3 * shorter leg</span>
Step-by-step explanation:
The equation that is given is only for the specific place of that object. To find the velocity, you need to take the derivative of the equation. This will give you:
Now, to find the average velocity of this object, plug in the values given to you. It's between the time interval [1, 2] so these are the two numbers you'll plug into the velocity equation. Finding this average is like finding any other average.
So
Average velocity is 0.5 sec
To find instantaneous velocity just find the velocity at time one. Think about the name "instantaneous velocity," it's the velocity in that <u>instant</u>.
We already found this, so I don't need more work (it's displayed above).
The instantaneous velocity when 
is 2.5 sec.
