Answer:
a) 

And we want the probability from 0 to two deviations above the mean and we got 95/2 = 47.5 %
b) 

So one deviation below the mean we have: (100-68)/2 = 16%
c) 

For this case below 2 deviation from the mean we have 2.5% and above 1 deviation from the mean we got 16% and then the percentage between -2 and 1 deviation above the mean we got: (100-16-2.5)% = 81.5%
Step-by-step explanation:
For this case we have a random variable with the following parameters:

From the empirical rule we know that within one deviation from the mean we have 68% of the values, within two deviations we have 95% and within 3 deviations we have 99.7% of the data.
We want to find the following probability:

We can find the number of deviation from the mean with the z score formula:

And replacing we got


And we want the probability from 0 to two deviations above the mean and we got 95/2 = 47.5 %
For the second case:


So one deviation below the mean we have: (100-68)/2 = 16%
For the third case:

And replacing we got:


For this case below 2 deviation from the mean we have 2.5% and above 1 deviation from the mean we got 16% and then the percentage between -2 and 1 deviation above the mean we got: (100-16-2.5)% = 81.5%
Answer:
the answer would be -13n-23
Step-by-step explanation:
first you want to distribute the brackets
-7(2+n) = -14-7n
+(-9-6n)
-9-6n
-14-7n-9-6n
combine the n value with an n value and an integer that doesn't have an n value
-7n-6n-14-9
= -13n-23
Answer:
4
Step-by-step explanation:
because i know how to do it
Answer:
3, 15, 14
Step-by-step explanation:
x + 5x + ( 5x -1) = 32
11x - 1 = 32
11x = 32 + 1
11x = 33
11x/11 = 33/11
x = 3
therefore
the first number is 3
the second is 5 × 3 = 15
the third number is 15 - 1 = 14
Answer:
<h2> 18.3</h2>
Step-by-step explanation:
from cosines theorem:
t² = 11² + 14² - 2•11•14•cos87°
t² = 121 + 196 + 308•0.05236
t² = 333.12688
t = √333.12688
t = 18.2517... ≈ 18.3