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gtnhenbr [62]
3 years ago
11

How much physical activity should an adult have each week?

Physics
2 answers:
LuckyWell [14K]3 years ago
7 0

Answer:d

Explanation:

zloy xaker [14]3 years ago
7 0
D. Hope this helps:)
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How much KCI can be dissolved in 100 g of water at 30°C?​
asambeis [7]

Answer:

34

Explanation:

The problem provides you with thesolubility of potassium chloride, KCl , in water at 20∘C , which is said to be equal to 34 g / 100 g H2O . This means that at 20∘C , a saturated solution of potassium chloride will contain 34 g of dissolved salt for every100 g of water.

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3 years ago
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A scientist mixes an unknown powder into a beaker of water. He then uses an indicator and finds that the pH of the resulting sol
zaharov [31]
A ph higher than 7 is basic so you can eliminate a.  The indicator can be used to measure both acids and bases so you can eliminate c.   Hydrogen ions are from acids, so the answer is that the powder decreased the hydrogen ions in the water.
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4 years ago
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Plz help i need help on my homework
tatiyna
The resultant force is 4 N to the right.
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4 years ago
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A convex lens has a focal length of 16.5 cm. Where on the lens axis should an object be placed in order to get a virtual, enlarg
alexandr402 [8]

Answer:

Object should be placed at a distance, u = 7.8 cm

Given:

focal length of convex lens, F = 16.5 cm

magnification, m = 1.90

Solution:

Magnification of lens, m = -\frac{v}{u}

where

u = object distance

v = image distance

Now,

1.90 = \frac{v}{u}

v = - 1.90u

To calculate the object distance, u by lens maker formula given by:

\frac{1}{F} = \frac{1}{u}+ \frac{1}{v}

\frac{1}{16.5} = \frac{1}{u}+ \frac{1}{- 1.90u}

\frac{1}{16.5} = \frac{1.90 - 1}{1.90u}

\frac{1}{16.5} = \frac{ 0.90}{1.90u}

u = 7.8 cm

Object should be placed at a distance of 7.8 cm on the axis of the lens to get virtual and enlarged image.

6 0
4 years ago
HELP PLZ!!<br> can the kinetic energy of an object be negative? explain
BARSIC [14]

Answer:

No it can not

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7 0
3 years ago
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