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slava [35]
2 years ago
11

The gravitational force between two objects is 2700 N. What will be the gravitational force between the objects if the distance

between them triples?
Physics
2 answers:
larisa [96]2 years ago
6 0
As two objects are separated from each other, the force of gravitational attraction between them also decreases. ... If the separation distance between any two objects is tripled (increased by a factor of 3), then the force of gravitational attraction is decreased by a factor of 9 (3 raised to the second power).
Musya8 [376]2 years ago
3 0

F = GMm/r^2

So F is proportional to 1/r^2

F2 = 2700 x ( 1 / 3^2 ) = 300N

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Ben hit a 0.25kg nail into a wood with a 5.2kg hammer. If the hammer moves witht the speed of 52 m/s and two fifth of its kineti
Art [367]

Answer:

Explanation:

Mass of nails is 0.25kg

Mass of hammer 5.2kg

Speed of hammer is =52m/s

Then, Ben kinetic energy is given as

K.E= ½mv²

K.E= ½×5.2×52²

K.E= 7030.4J

Given that, two-fifth of kinetic energy is converted to internal energy

Internal energy (I.E) = 2/5 × K.E

Internal energy (I.E) = 2/5 × 7030.4

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∆Et= K.E-I.E

∆Et= 7030.4 - 2812.16

∆Et= 4218.24J

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3 years ago
A mixture in which the parts can be seen separately from the other parts is considered to be what type of mixture
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6 0
3 years ago
A jogger hears a car alarm and decides to investigate. While running toward the car, she hears an alarm frequency of 872.10 Hz.
Nata [24]

Answer:

v = 4.18 m/s

Explanation:

given,

frequency of the alarm = 872.10 Hz

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speed of the jogger = ?

speed of the

v_f = \dfrac{872.10-851.10}{2}

v_f =10.5\ Hz

v_o = 872.1 - 10.5

V_0 = 861.6\ Hz

The speed of jogger

v = \dfrac{v_1 \times 343}{v_0}-343

v = \dfrac{872.1 \times 343}{861.6}-343

v = 4.18 m/s

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Vera_Pavlovna [14]

Answer:

A, B, C, E

Explanation:

now gimme thanks please

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3 years ago
Read 2 more answers
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