Answer:
Neptune is approximately 41 times as far from the sun as Venus
Explanation:
Estimate = distance of Neptune from the sun ÷ distance of Venus from the sun = 4.5×10^9 ÷ 1.18×10^8 = 40.9 (approximately 41)
 
        
             
        
        
        
Answer:
The batteries would be connected in series while the bulbs would be connected in parallel
Explanation:
Power (W) = VI 
where V = voltage, I = current and R = resistance 
from V = IR , I = V/R
Power (W) now becomes = V (V/R) = 
Power (W) =  
from the above equation, power is directly dependent on voltage, hence the voltage has to be high for the power to be high and the power is also inversely dependent on the resistance (in this case the bulbs which act as the load)
- We have to batteries, when batteries are connected in series the total voltage becomes the summation of the two voltages hence giving a higher voltage and when they are connected in parallel their voltage remains the same. Since we want to get higher voltage we will connect the two batteries in series.
- we have two bulbs which are the resistance here, from the equation above the power is inversely dependent on the resistance so we would need its value to be minimal. When resistance is connected in series the resistance individual will be added to get the total resistance, hence the total resistance will be high but when the resistors are arranged in parallel you get the total resistance by applying the formula  which will give us a lower resistance. Hence we would connect the bulbs in parallel. which will give us a lower resistance. Hence we would connect the bulbs in parallel.
Take note that the power from this connection should not exceed the bulbs power rating so as to avoid damage of the bulbs.
 
        
             
        
        
        
Answer:
4.8 mph
Explanation:
From the question,
Average speed = total distance/total time
V = d/t....................... Equation 1
Where d = distance, t = time
Given: d = 26.2 miles, t = 5.5 hours.
Substitute these values into equation 1
V = 26.2/5.5
V = 4.76 mph
V ≈ 4.8 mph
 
        
                    
             
        
        
        
The Period of the resulting shm will be T=39.7
<u>Explanation:</u>
<u>Given data</u>
m=3kg
d=.06m
k=1200 N/m
Θ=3 °
T=?
we have the formulas,
I = (1/6)Md2 
F = ma 
F = -kx = -(mω2x)
 k = mω2 τ = -d(FgsinΘ)
T=2 x 3.14/ √(m/k)
Solution for the given problem would be,
F=-Kx (where x= dsin Θ)
F=-k dsin Θ
F=-(1200)(.06)sin(3 °)
F=-10.16N
<u>By newton's second law.</u>
F = ma 
a= F/m
a=(-10.16N)/3
a=3.38
<u>using the k=mω value</u>
k=mω
ω=k/m
ω=1200/3
ω=400
<u>Using F = -kx value</u>
 x = F/-k
x=(-10.16)/1200
x=0.00847m
<u>Restoring the  torque value </u>
τ = -dmgsinΘ    where( τ = Iα so.).. Iα = -dmgsinΘ α = -(.06)(4)α = 
α =(.06)(4)(9.81)sin(4°) 
α=-1.781
<u>Rotational to linear form</u>
 a = αr  
r = .1131 m 
a=-1.781 x .1131 m 
a=-0.2015233664
<u>Time Period</u>
T=2 x 3.14/ √(m/k)
T=6.28/√(3/1200)
T=6.28/0.158
T=39.7
 
        
             
        
        
        
Answer:
stop using brainly and learn this bs in class
Explanation: