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3 years ago

Why do the planets orbit the Sun in an elliptical shape?

Physics

1 answer:

ki77a [65]3 years ago

7 0

Answer:

That's essentially how objects in orbits work as they move closer to the body they orbit, they accelerate faster and faster. Our penny will get so fast that, once it comes around the planet, it will be flung very far away, which will then slow it down. This is what creates an elliptical orbit.

Explanation:

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A coaxial cable consists of alternating coaxial cylinders of conducting and insulating material.

olga2289 [7]

Answer:

True

Explanation:

A coaxial cable is a type of cable that has an inner conductor surrounded by an insulating layer, surrounded by a conductive shielding.

4 0

3 years ago

How do you measure mass? Need now!

Yakvenalex [24]

With a ruler and a calculator

7 0

4 years ago

Read 2 more answers

A ball is attached to a string of length 3 m to make a pendulum. The pendulum is placed at a location that is away from the Eart

Musya8 [376]

1) $0.61 m/s^2$

2) 13.9 s

Explanation:

The acceleration due to gravity is the acceleration that an object in free fall (acted upon the force of gravity only) would have.

It can be calculated using the equation:

$g=\frac{GM}{r^2}$ (1)

where

G is the gravitational constant

$M=5.98\cdot 10^{24} kg$ is the Earth's mass

r is the distance of the object from the Earth's center

The pendulum in the problem is at an altitude of 3 times the radius of the Earth (R), so its distance from the Earth's center is

$r=4R$

where

$R=6.37\cdot 10^6 m$ is the Earth's radius

Therefore, we can calculate the acceleration due to gravity at that height using eq.(1):

$g=\frac{GM}{(4R)^2}=\frac{(6.67\cdot 10^{-11})(5.98\cdot 10^{24})0.}{(4\cdot 6.37\cdot 10^6)^2}=0.61 m/s^2$

The period of a simple pendulum is the time the pendulum takes to complete one oscillation. It is given by the formula

$T=2\pi \sqrt{\frac{L}{g}}$

where

L is the length of the pendulum

g is the acceleration due to gravity at the location of the pendulum

Note that the period of a pendulum does not depend on its mass.

For the pendulum in this problem, we have:

L = 3 m is its length

$g=0.61 m/s^2$ is the acceleration due to gravity (calculated in part 1)

Therefore, the period of the pendulum is:

$T=2\pi \sqrt{\frac{3}{0.61}}=13.9 s$

4 0

3 years ago

Explain how science can help people save resources such as coal?

solong [7]

Science can be used to look for other renewable resources than mining for coal

8 0

4 years ago

A force of 6.0 N is applied horizontally to a 3.0 kg crate initially at rest on a horizontal frictionless surface. After the cra

Savatey [412]

Answer:

a. Yes, because the acceleration of the crate is 2.0 m/s².

Explanation:

Given

$Force = 6N$ --- f

$Mass = 3kg$ --- m

$Time = 1.5s$ --- t

$Velocity = 3.0m/s$ --- v

Required

Does the system support $F=ma$

Yes, it does and this is shown below

The crate is initially at rest; so:

$u = 0$

Using the first equation of motion

$v = u + at$

Substitute values for v, u and t

$3 = 0 + a*1.5$

$3 = 1.5a$

Make a the subject

$a = 3/1.5$

$a = 2$

Using $F = ma$

Substitute values for F and m

$6 = 3 * a$

Divide both sides by 3

$6/3 = 3/3 * a$

$2 = a$

$a = 2$

In both cases:

$a = 2$

<em>Hence, option (a) is correct.</em>

6 0

3 years ago