Which are examples of stress that are not chronic or persistent?

5. {Chapter 6 Suppose you are traveling down the road in your car at highway speeds on a nice

Hitman42 [59]

Answer:

a) The 2 forces are equal

b) The impulse is the same

c) The change in momentum is the same

d) Inelastic

Explanation:

a)

According to Newton's third law of motion:

"When an object A exerts a force on an object B (action force), then object B exerts an equal and opposite force on object A (reaction force)"

In this problem, we can identify:

- The car as object A

- The bug as object B

Therefore:

- The force exerted by the car on the bug is the action force

- The force exerted by the bug on the car is the reaction force

According to Newton's third law of motion, these two forces are equal in magnitude, and opposite in direction.

b)

The impulse exerted on an object is equal to the product between the force exerted on it and the time taken:

$I=F\Delta t$

where

I is the impulse

F is the force exerted

$\Delta t$ is the time during which the force is applied

In this problem:

- The force F exerted on both the car and the bug is the same (according to what we said in part a)

- The time interval $\Delta t$ is the same for the two objects

Therefore, the impulse exerted on the bug is the same as the impulse on the car.

c)

The change in momentum of an object is defined as:

$\Delta p = m \Delta v$ (1)

where

m is the mass of the object

$\Delta v$ is the change in velocity of the object

However, according to the impulse theorem, the change in momentum of an object is also equal to the impulse it has experienced:

$\Delta p = I$

Therefore, since the impulse experienced by the bug and the car is the same (part b), this means that the change in momentum of the bug and the car is the same (and so by looking at eq.(1), we can conclude that the bug will experience a larger change in velocity, since its mass is smaller than that of the car).

d)

There are two types of collision:

Elastic collision: in an elastic collision, both the total momentum and the total kinetic energy of the system are conserved
Inelastic collision: in an inelastic collision, only the total momentum is conserved, while the total kinetic energy is not (part of the energy is converted into thermal energy due to the presence of friction forces)

In particular, inelastic collision occurs when the two objects stick together after the collision.

In this situation, we see that the bug and the car stick together after the collision: this means that the total kinetic energy of the system is not conserved, and therefore, this is an example of inelastic collision.

5 0

3 years ago

A mechanic uses a mechanical lift to raise a car. The car weighs 11,000 N. The lift raises the car 2.5 m.

KengaRu [80]

Potential energy = (weight) x (height)

After the car has been raised 2.5 meters, it has

(11,000) x (2.5) = 27,500 Joules

MORE potential energy than it had before it was lifted.

That's the energy that has to come from the work you do to lift it.

Since no mechanical process is ever 100% efficient, the work required
to accomplish this task is <em>at least 27,500 joules</em>.

5 0

3 years ago

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How do solutions differ from other mixtures?

zalisa [80]

The answer is D.
I hope this helps.

7 0

3 years ago

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A crane is lifting a 500 lb piano with a velocity of 2fts''. Express the power of the crane in hp. (1 hp = 550ft-lbs)

Sonja [21]

Answer:

goalindia

goalindiaGiven:

goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kg

goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 W

goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:

goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:The velocity of the car.

goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:The velocity of the car.Calculation:

goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:The velocity of the car.Calculation:- The Power can be given by the formula:

goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:The velocity of the car.Calculation:- The Power can be given by the formula:P = F × v

goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:The velocity of the car.Calculation:- The Power can be given by the formula:P = F × v⇒ v = P/F

goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:The velocity of the car.Calculation:- The Power can be given by the formula:P = F × v⇒ v = P/F⇒ v = P/mg

goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:The velocity of the car.Calculation:- The Power can be given by the formula:P = F × v⇒ v = P/F⇒ v = P/mg⇒ v = 1357.72/(226.8 × 9.8)

goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:The velocity of the car.Calculation:- The Power can be given by the formula:P = F × v⇒ v = P/F⇒ v = P/mg⇒ v = 1357.72/(226.8 × 9.8)⇒ v = 1357.72/2222.64

goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:The velocity of the car.Calculation:- The Power can be given by the formula:P = F × v⇒ v = P/F⇒ v = P/mg⇒ v = 1357.72/(226.8 × 9.8)⇒ v = 1357.72/2222.64⇒ v = 0.61 m/s

goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:The velocity of the car.Calculation:- The Power can be given by the formula:P = F × v⇒ v = P/F⇒ v = P/mg⇒ v = 1357.72/(226.8 × 9.8)⇒ v = 1357.72/2222.64⇒ v = 0.61 m/s- So, the velocity of the car will be 0.61❤

6 0

2 years ago

As longitudional waves travel, particles in the medium are pushed together and then pulled apart. We call this

lawyer [7]

Compression and rarefaction.

4 0

4 years ago

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