The specific gravity is the ratio of the density of oil to the density of water. Since the density of water is 1g/ml, the density of a substance is numerically the same as the specific gravity.
However, specific gravity is a dimensionless number, while density has units mass/volume.
So, the density of oil is .901 g/ml, but the specific gravity is just .901
In Imperial units, the density of the oil is 56.2 lb/ft^3, but the specific gravity is still .901
STP (Standard Temperature and Pressure) has the following conditions:
Temperature = 273.15 K = 0°C
Pressure = 101325 Pa = 101.325 KPa = 1 atm
We also know that 1 mole = 6.022x10^23 molecules
Using the ideal gas equation: PV=nRT
n/V = P/RT
molecules/V = P*6.022x10^23/RT
molecules/V = 101325 Pa (6.022x10^23 molecules/mole)/ (8.314 Pa-m3/mol-K)(273.15K)
molecules/V = 7.339x10^27 molecules/m^3 - Final answer
Answer:
continue moving with constant velocity
Explanation:
Answer:
No, the magnitude of the magnetic field won't change.
Explanation:
The magnetic field produced by a wire with a constant current is circular and its flow is given by the right-hand rule. Since this field is circular with center on the wire the magnitude of the magnetic field around the wire will be given by B = [(\mi_0)*I]/(2\pi*r) where (\mi_0) is a constant, I is the current that goes through the conductor and r is the distance from the wire. If the field sensor will move around the wire with a fixed radius the distance from the wire won't change so the magnitude of the field won't change.
Answer:
2621.25 meters
Explanation:
First, write down what we are given.
Initial velocity = 27.5 m/s
Final velocity = 42.4 m/s
Time = 75 seconds
We need to look at the kinematic equations and determine which one will be best. In this case, we need an equation with distance. I am going to use
, but you can also use the other equation, 
We need to find acceleration. To find it, we need to use the formula for acceleration:
. Plugging in values, 
Next, plug in what we know into the kinematics equation and solve for distance. 