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ICE Princess25 [194]
3 years ago
8

Two forces and are applied to an object whose mass is 13.3 kg. The larger force is . When both forces point due east, the object

's acceleration has a magnitude of 0.723 m/s2. However, when points due east and points due west, the acceleration is 0.493 m/s2, due east. Find (a) the magnitude of and (b) the magnitude of .
Physics
1 answer:
ANEK [815]3 years ago
6 0

Answer:

Explanation:

First, It's important to remember F = ma, and in this problem m = 13.3 kg

This can be reduced to a simple system of equations problem.  Now if they are both going the same way then we add them, while if they are going the opposite way we subtract them.  So let's call them F1 and F2, with F1 arger than F2.  Now, When we add them together F1+F2 = (.723 m/s^2)*13.3kg and then when we subtract them, and have the larger one pushing toward the east, let's call F1 the larger one, F1-F2 = (.493 m/s^2)*13.3kg.  

Can you solve this system of equations seeing them like this, or do you need more help?

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The election of 2008 had a record-breaking number of voters. It had the highest percentage of eligible voters voting in more tha
babunello [35]

Answer:

People were particularly motivated by one of the candidates

Explanation:

The voter turnout in 2008 spiked because people were particularly motivated by Barrack Obama. His running for presidential position represented a <em>"generational change."</em> So, this means that many of the voters, especially the African-Americans ages 18 to 25 years old became interested in registering in order to vote.

Such kind of voter turnout spike is said to have also occurred during the candidacy of John F. Kennedy, where the voter turnout was<em> 62.8 percent.</em> This was because Kennedy was a <em>charismatic leader</em> who also represented a <u>generational change</u>.

So, this explains the answer.

4 0
3 years ago
A blinking light of constant period is situated on a lab cart. Which diagram best represents a photograph of light, taken every
Karo-lina-s [1.5K]

The snapshot of light as the cart moves with constant velocity is represented by a graph with uniform displacement at each time interval.

The change in displacement with time is uniform at constant velocity. The displacement of the supplied moving item grows at the same pace.

The beginning velocity equals the ultimate velocity at constant velocity.

v₁ = v₂

The object's acceleration at constant velocity is zero since the velocity change with time is zero.

As a result, we may deduce that the graph with equal displacement at each time interval reflects a snapshot of light as the cart moves at a constant speed.

A moving object's displacement-time graph shows the distance traveled by a moving item as time passes. A vector quantity is displacement. The slope or gradient of this graph represents the velocity of the item. The displacement-time graph, also known as the position-time graph, describes an object's motion. In this graph, the displacement of the moving item is displayed on the y-axis as a dependent variable, while time is shown on the x-axis as an independent variable.

Learn more about Uniform displacement here:

brainly.com/question/22102874

#SPJ1

3 0
2 years ago
An automobile is traveling on a long, straight highway at a steady 80.0 mi/h when the driver sees a wreck 190 m ahead. At that i
kozerog [31]

Answer:

a) The car’s speed just after leaving the icy portion of the road is the first part

Explanation:

6 0
3 years ago
Tlo
kondor19780726 [428]

Answer:

9.949 m

Explanation:

From the question,

L' = L+LαΔT................. Equation 1

Where L' = New length, L = Original length, α = linear expansivity of Cu, ΔT = change in temperature

Given: L = 10 m, α  = 0.00017 K⁻¹, ΔT = 50-80

L' = 10+10(0.00017)(50-80)

L' = 10-0.051

L' = 9.949 m

Hence the new legth of Cu is  9.949 m

5 0
3 years ago
One kilowatt-hour (kWh) is the amount of work or energy generated when one kilowatt of power is supplied for a time of one hour.
Helga [31]

Answer:

The energy in one kilowatt-hour is 36\times10^{5}\ J

Explanation:

Given that,

Power = 1 kW

Time = 1 hour

One kilowatt-hour (kWh) is the amount of work or energy generated when one kilowatt of power is supplied for a time of one hour

We need to calculate the energy

Using formula of energy

E=p\times t

Where, P = power

t = time

Put the value into the formula

E=1\times10^{3}\times3600

E=36\times10^{5}\ J

Hence, The energy in one kilowatt-hour is 36\times10^{5}\ J

6 0
4 years ago
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