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ICE Princess25 [194]
2 years ago
8

Two forces and are applied to an object whose mass is 13.3 kg. The larger force is . When both forces point due east, the object

's acceleration has a magnitude of 0.723 m/s2. However, when points due east and points due west, the acceleration is 0.493 m/s2, due east. Find (a) the magnitude of and (b) the magnitude of .
Physics
1 answer:
ANEK [815]2 years ago
6 0

Answer:

Explanation:

First, It's important to remember F = ma, and in this problem m = 13.3 kg

This can be reduced to a simple system of equations problem.  Now if they are both going the same way then we add them, while if they are going the opposite way we subtract them.  So let's call them F1 and F2, with F1 arger than F2.  Now, When we add them together F1+F2 = (.723 m/s^2)*13.3kg and then when we subtract them, and have the larger one pushing toward the east, let's call F1 the larger one, F1-F2 = (.493 m/s^2)*13.3kg.  

Can you solve this system of equations seeing them like this, or do you need more help?

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Answer:

360 N

Explanation:

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Since the object has an initial velocity of 2 m/s and acceleration of -2 m/s/s

the object will come to rest in 1 second but the force applied in that one second can be calculated by:

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Now, calculating the force applied on the box due to gravity

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F = -300 N (the negative sign tells us that the force is acting downwards)

Now, calculating the total downward force:

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<em></em>

<em>Hence, a downward force of 360 N is being applied on the box and since the box did not disconnect from the rope, the rope applied the same amount of force in the opposite direction</em>

Therefore tension on the force = <u>360 N</u>

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Answer:

0.1 s

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