Answer:
$4.2
Explanation:
Given data
Power= 700W
time= 10 hours
Cost per kilowatt hours is cents $0.20
Let us find the number of hours in a month
=24*30
=720 hours
Energ= power*time
Energy= 700/1000*30
Energy= 7*3
Enery= 21 kwh
1 kwh= 0.2
21kwh= x
cross multiply
x=21*0.2
x= $4.2
A 15.75-g<span> piece of iron absorbs 1086.75 </span>joules<span> of </span>heat<span> energy, and its ... </span>How many joules<span> of </span>heat<span> are </span>needed<span> to raise the temperature of 10.0 </span>g<span> of </span>aluminum<span> from 22°C to 55°C, if the specific </span>heat<span> of </span>aluminum<span> is o.90 J/</span>g<span>”C2 .</span>
Explanation:
1. Acceleration is the change in velocity over time.
a = Δv / Δt
a = (29.8 m/s − 37.1 m/s) / 3 s
a = -2.43 m/s²
2. Work equals force times distance.
W = Fd
W = (87.3 N) (2.04 m)
W = 178 J
3. Power is work per time.
P = W / t
267 W = 1250 J / t
t = 4.68 s
Explanation:
answer is the 3rd law of motion
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