The correct equation for: iron + sulfur -> iron (III) sulfide is D
Answer:
Net number of sigma bonds = 1
Net number of pi bonds = 2
Overall bond order = 3
Explanation:
Electronic configuration of N2 ia
1s2 2s2 2p3
There is head to head overlap in pz orbital. Thus, there is one sigma bond
Pi bond is formed whenever there is side wise overlapping. Since both px and py undergoes overlapping to form pi bond, there are two pi bonds
Bond order = 0.5 (bonding electron – antibonding electron)
= 0.5 (8-2) = 0.5*6 = 3
Answer:The correct answer is ;
The oxidation state of nitrogen in NO changes from +2 to 0, and the oxidation state of carbon in CO changes from +2 to +4 as the reaction proceeds.
Explanation:
In an oxidation recation addition of oxygen atom takes place or loss of electrons takes place.
In an reduction reaction removal of oxygen atom takes place or gain of electrons takes place.
In the given reaction , the nitrogen atom is present in +2 oxidation state in NO molecule and present in 0 oxidation state in 
molecule. Hence, nitrogen is getting reduced that is reduction reaction. NO is oxidizing agent
In the given reaction , the carbon atom is present in +2 oxidation state in CO molecule and present in +4 oxidation state in 
molecule. Hence ,carbon is getting oxidized that is oxidation reaction. CO is a reducing agent.
Halogen--Florine
Chalogen-- Oxygen
Alkali Metal-- Sodium
Boron -- Metalloid (atomic symbol B)
Lanthanide series-- (Number 57-71 on periodic Table) Example: Cerium #58
Alkaline Earth Metal--Magnesium
Transition Metal-- Gold, Iron, Silver. Etc... (Middle section of a period table)
Nobel Gas--Helium
Answer:
a. True
Explanation:
From the basic concepts of acids and bases, we know that when a base accepts a hydrogen ion (H⁺), it forms a conjugate acid which can accept again the H⁺ ion:
B⁻ + H₂O ⇆ BH + OH⁻
The stronger the base, the weaker the conjugate base. Thus, as more strength has a base, lesser strength will have the conjugate base (it will not be able to accept again the H⁺ ion). For example, when water (H₂O) loses its H⁺ , it forms the conjugate base OH⁻. So, OH⁻ is the stronger base that can exist in an aqueous solution.
H₂O ⇆ H⁺ + OH⁻
In fact, strong bases are hydroxides, such as NaOH or KOH.
