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3 years ago

The following reaction occurs in a car’s catalytic converter.

Chemistry

2 answers:

blagie [28]3 years ago

8 0

Answer:The correct answer is ;

The oxidation state of nitrogen in NO changes from +2 to 0, and the oxidation state of carbon in CO changes from +2 to +4 as the reaction proceeds.

Explanation:

$2NO(g)+2CO(g)\rightarrow N_2(g)+2CO_2(g)$

In an oxidation recation addition of oxygen atom takes place or loss of electrons takes place.

In an reduction reaction removal of oxygen atom takes place or gain of electrons takes place.

In the given reaction , the nitrogen atom is present in +2 oxidation state in NO molecule and present in 0 oxidation state in $N_2$ molecule. Hence, nitrogen is getting reduced that is reduction reaction. NO is oxidizing agent

In the given reaction , the carbon atom is present in +2 oxidation state in CO molecule and present in +4 oxidation state in $CO_2$ molecule. Hence ,carbon is getting oxidized that is oxidation reaction. CO is a reducing agent.

motikmotik3 years ago

6 0

<u>Answer: </u>The correct statement is the oxidation state of nitrogen in NO changes from +2 to 0, and the oxidation state of carbon in CO changes from +2 to +4 as the reaction proceeds.

<u>Explanation:</u>

Oxidizing agent is the agent which oxidizes the other substance and itself gets reduced. The reaction it undergoes is reduction reaction. It gains electrons and the oxidation state of the substance gets reduced.

Reducing agent is the agent which reduced the other substance and itself gets oxidized. The reaction it undergoes is oxidation reaction. It looses its electrons and the oxidation state of the substance is increased

For the given chemical equation:

$2NO(g)+2CO(g)\rightarrow N_2(g)+2CO_2(g)$

<u>On reactant side:</u>

Oxidation state of Nitrogen = +2

Oxidation state of Carbon = +2

Oxidation state of Oxygen = -2

<u>On product side:</u>

Oxidation state of Nitrogen = 0

Oxidation state of Carbon = +4

Oxidation state of Oxygen = -2

The oxidation state of carbon is increasing from +2 to +4, it is loosing electrons and thus it is undergoing oxidation reaction and CO is considered as a reducing agent. And the oxidation state of Nitrogen in reducing from +2 to 0, it is gaining electrons and thus it is undergoing reduction reaction and is considered as an oxidizing agent.

Hence, the correct statement is the oxidation state of nitrogen in NO changes from +2 to 0, and the oxidation state of carbon in CO changes from +2 to +4 as the reaction proceeds.

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Based on your observations, which equation best models the reaction of vinegar (C2H4O2) and baking soda (NaHCO3)? Explain.

tensa zangetsu [6.8K]

Answer: im in 8th they got me doin this

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3 years ago

Are the following combinations allowed? If not, show two ways to correct them:

mafiozo [28]

The following combination of n=3 ; l=1 ; ml=-2 is not allowed. One way to correct this would be by changing the azimuthal quantum number, l and the other way would be to change the magnetic quantum number, m.

<h3>Is the following combination n=3; l=1; ml=-2 allowed or not.? If not, suggest two ways through which it can be corrected.</h3>

The following combination of n=3 ; l=1 ; ml=-2 is not allowed.

There are several rules that need to be followed for assigning electron quantum numbers. They are:

1. Principal quantum number should be 1 ≤ n

2. Azimuthal quantum number, 0 ≤ l ≤ n − 1

3. Magnetic quantum number, -l ≤ ml ≤ l

4. Spin quantum number as either -1/2 or +1/2

For n = 3,

l should be n - 1 or n - 2 or n - 3 = 2, 1, 0 respectively.

If we choose l = 1 then ml should be -1, 0 and +1

Therefore, one way to correct the combination would be to change the magnetic quantum number to -1

If we choose l = 2 then ml would be -2, -1, 0, +1, +2

Thus, another way to correct the combination is to choose the azimuthal quantum number as 2.

Thus, the following combination of n=3; l=1; ml=-2 is not allowed. One way to correct this would be by changing the azimuthal quantum number, l and the other way would be to change the magnetic quantum number, m.

To learn more about quantum numbers refer:

brainly.com/question/5927165

#SPJ4

5 0

2 years ago

How many moles of oxygen (O2) are present in 33.6 L of the gas at 1 atm and 0°C?

maw [93]

Answer: 1.5

Explanation:

Just took the test on E2020!

3 0

3 years ago

Which of the following would not be found in an atom?

Korvikt [17]

<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ It would be B. An Ion.

Ions aren't found in atoms - it is atoms that can become ions by gaining or losing electrons.

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

3 0

4 years ago

Read 2 more answers

1)If I mixed salt in water I would expect the salt to:

zaharov [31]

Answer:

1)If I mixed salt in water I would expect the salt to: dissolve.

2) If I mixed starch in water I would expect the starch to: remain undissolved.

Explanation:

Hello,

In this case, since salt, which is commonly known as sodium chloride (NaCl) is an ionic compound, it is very likely to get dissolved in water, therefore, we would expect the salt to dissolve and form a liquid solution.

Moreover, since start is mainly composed by C-C, C-O and C-H bonds which are nonpolar, it we can say it is usually insoluble in water, therefore we will expect starch to remain undissolved but undergoing a process called gelatinization in which a suspension in formed until a slightly solid consistency.

Best regards.

4 0

3 years ago