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3 years ago

The following reaction occurs in a car’s catalytic converter.

Chemistry

2 answers:

blagie [28]3 years ago

8 0

Answer:The correct answer is ;

The oxidation state of nitrogen in NO changes from +2 to 0, and the oxidation state of carbon in CO changes from +2 to +4 as the reaction proceeds.

Explanation:

$2NO(g)+2CO(g)\rightarrow N_2(g)+2CO_2(g)$

In an oxidation recation addition of oxygen atom takes place or loss of electrons takes place.

In an reduction reaction removal of oxygen atom takes place or gain of electrons takes place.

In the given reaction , the nitrogen atom is present in +2 oxidation state in NO molecule and present in 0 oxidation state in $N_2$ molecule. Hence, nitrogen is getting reduced that is reduction reaction. NO is oxidizing agent

In the given reaction , the carbon atom is present in +2 oxidation state in CO molecule and present in +4 oxidation state in $CO_2$ molecule. Hence ,carbon is getting oxidized that is oxidation reaction. CO is a reducing agent.

motikmotik3 years ago

6 0

<u>Answer: </u>The correct statement is the oxidation state of nitrogen in NO changes from +2 to 0, and the oxidation state of carbon in CO changes from +2 to +4 as the reaction proceeds.

<u>Explanation:</u>

Oxidizing agent is the agent which oxidizes the other substance and itself gets reduced. The reaction it undergoes is reduction reaction. It gains electrons and the oxidation state of the substance gets reduced.

Reducing agent is the agent which reduced the other substance and itself gets oxidized. The reaction it undergoes is oxidation reaction. It looses its electrons and the oxidation state of the substance is increased

For the given chemical equation:

$2NO(g)+2CO(g)\rightarrow N_2(g)+2CO_2(g)$

<u>On reactant side:</u>

Oxidation state of Nitrogen = +2

Oxidation state of Carbon = +2

Oxidation state of Oxygen = -2

<u>On product side:</u>

Oxidation state of Nitrogen = 0

Oxidation state of Carbon = +4

Oxidation state of Oxygen = -2

The oxidation state of carbon is increasing from +2 to +4, it is loosing electrons and thus it is undergoing oxidation reaction and CO is considered as a reducing agent. And the oxidation state of Nitrogen in reducing from +2 to 0, it is gaining electrons and thus it is undergoing reduction reaction and is considered as an oxidizing agent.

Hence, the correct statement is the oxidation state of nitrogen in NO changes from +2 to 0, and the oxidation state of carbon in CO changes from +2 to +4 as the reaction proceeds.

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11111nata11111 [884]

The correct answer is B. Homeostasis

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2 years ago

How many grams of hydrogen gas would be needed to form 8.0 grams of water? H2+O2=H2O

damaskus [11]

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3 years ago

(h) The student made observations related to the contents of the Erlenmeyer flask during the titration. Identify an observation

katen-ka-za [31]

Answer:

Explanation:

During titration indicators are often used to identify chemical changes between reacting species.

For colorless solutions in which no noticeable changes can easily be seen, indicators are the best bet. Most titration processes involves a combination of acids and bases to an end point.

Indicators are substances whose color changes to signal the end of an acid-base reaction. Examples are methyl orange, methyl red, phenolphthalein, litmus, cresol red, cresol green, alizarin R3, bromothymol blue and congo red.

Most of these indicators have various colors when chemical changes occur.

Also, there are heat changes that accompanies most of these reactions. These are also indicators of chemical changes.

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3 years ago

2. A 2.5 mol SAMPLE OF OXYGEN GAS (O2) INCREASES TO 3.2 mol

lana [24]

696.32 mmHg is the final pressure of the gas.

<h3>What is an ideal gas equation?</h3>

The ideal gas equation, pV = nRT, is an equation used to calculate either the pressure, volume, temperature or number of moles of a gas.

Given data:

$P_1$ = 720 mmHg

$P_2$ = ?

$n_1$ = 2.5 mol

$n_2$ = 3.2 mol

$V_1$ = 34 L

$V_2$ = 45 L

Formula

Combined gas law

$\frac{P_1 V_1}{n_1} = \frac{P_2 V_2}{n_2}$

$P_2$ = 696.32 mmHg

Hence, 696.32 mmHg is the final pressure of the gas.

Learn more about an ideal gas equation here:

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2 years ago

Level 1: 2Sr + 02 > 2Sro

tekilochka [14]

Answer:

Sr would be the limiting reactant

5 moles

Explanation:

Since the equation is a balanced equation, the coefficient shows how each substance relates to the other in terms of the number of moles.

Reactants would be those on the left hand side of the arrow, while the products would be found on te right and side of the arrow. In this question, the reactants would be Sr and O₂.

Limiting reactant is the reactant that is insufficient; meaning to say that there is not enough of that substance and thus the reaction cannot continue. The other reactant(s) that is not limiting is called the excess reactants.

From the balanced equation, 2 moles of Sr is needed to react with 1 mole of O₂. Thus, if we have 5 moles of each reactant, Sr would be the limiting reactant since for every 1 mole of O₂, there has to be 2 moles of Sr in order for the reaction to proceed. Thus, if we have 5 moles of O₂, we would need 10 moles of Sr.

When we work out the amount of products formed, we look at the number of moles of the limiting reactant. This is because the limiting reactant determines how much is being reacted, while the excess number of moles of the excess reactant will remain unreacted.

For every 2 moles of Sr reacted, 2 moles of SrO would be produced. This means that the mole ratio of Sr to SrO is 1:1. Thus, since 5 moles of Sr has been reacted, 5 moles of the product (SrO) would be produced.

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3 years ago