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3 years ago

The following reaction occurs in a car’s catalytic converter.

Chemistry

2 answers:

blagie [28]3 years ago

8 0

Answer:The correct answer is ;

The oxidation state of nitrogen in NO changes from +2 to 0, and the oxidation state of carbon in CO changes from +2 to +4 as the reaction proceeds.

Explanation:

$2NO(g)+2CO(g)\rightarrow N_2(g)+2CO_2(g)$

In an oxidation recation addition of oxygen atom takes place or loss of electrons takes place.

In an reduction reaction removal of oxygen atom takes place or gain of electrons takes place.

In the given reaction , the nitrogen atom is present in +2 oxidation state in NO molecule and present in 0 oxidation state in $N_2$ molecule. Hence, nitrogen is getting reduced that is reduction reaction. NO is oxidizing agent

In the given reaction , the carbon atom is present in +2 oxidation state in CO molecule and present in +4 oxidation state in $CO_2$ molecule. Hence ,carbon is getting oxidized that is oxidation reaction. CO is a reducing agent.

motikmotik3 years ago

6 0

Answer: The correct statement is the oxidation state of nitrogen in NO changes from +2 to 0, and the oxidation state of carbon in CO changes from +2 to +4 as the reaction proceeds.

Explanation:

Oxidizing agent is the agent which oxidizes the other substance and itself gets reduced. The reaction it undergoes is reduction reaction. It gains electrons and the oxidation state of the substance gets reduced.

Reducing agent is the agent which reduced the other substance and itself gets oxidized. The reaction it undergoes is oxidation reaction. It looses its electrons and the oxidation state of the substance is increased

For the given chemical equation:

$2NO(g)+2CO(g)\rightarrow N_2(g)+2CO_2(g)$

On reactant side:

Oxidation state of Nitrogen = +2

Oxidation state of Carbon = +2

Oxidation state of Oxygen = -2

On product side:

Oxidation state of Nitrogen = 0

Oxidation state of Carbon = +4

Oxidation state of Oxygen = -2

The oxidation state of carbon is increasing from +2 to +4, it is loosing electrons and thus it is undergoing oxidation reaction and CO is considered as a reducing agent. And the oxidation state of Nitrogen in reducing from +2 to 0, it is gaining electrons and thus it is undergoing reduction reaction and is considered as an oxidizing agent.

Hence, the correct statement is the oxidation state of nitrogen in NO changes from +2 to 0, and the oxidation state of carbon in CO changes from +2 to +4 as the reaction proceeds.

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ch4aika [34]

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3 years ago

The compound methylamine, CH3NH2, is a weak base when dissolved in water. Write the Kb expression for the weak base equilibrium

Veronika [31]

Answer:

Kb = [CH₃NH₃⁺] × [OH⁻] / [CH₃NH₂]

Explanation:

According to Brönsted-Lowry acid-base theory:

An acid is a substance that donates H⁺.
A base is a substance that accepts H⁺.

When methylamine reacts with water, it behaves as a Brönsted-Lowry base, according to the following reaction.

CH₃NH₂(aq) + H₂O(l) ⇄ CH₃NH₃⁺(aq) + OH⁻(aq)

The basic equilibrium constant (Kb) is:

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3 0

3 years ago

Which conversion factor is needed to solve the following problem?

77julia77 [94]

It is going to be Molar Volume
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5 0

3 years ago

What is the difference between a material having the chemical property of being flammable vs having the chemical property of bei

makkiz [27]

Answer:

Being flammable means it supports burning,e.g. Oxygen, but being combustible means burning itself too. e.g. Hydrogen.

Explanation:

Hope it helps!!

4 0

3 years ago

Why can some metals be extracted from compounds by heating with carbon and why can some not

pentagon [3]

Answer:

Some metals can be extracted from compounds by heating with carbon atom because they are less reactive than carbon and some metals cannot be extracted because they are more reactive than carbon atom.

Explanation: If the metal is less reactive than carbon atom so the carbon atoms make bond with oxide or other atom present with metal and the metal is free from that oxide or that element. But if the reactivity of metal is higher than carbon is unable to remove the oxide or element.

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3 years ago