Answer:
hco3
Explanation: bc i said so
Answer:
3.0585147719047385 is the answer
Answer: 0.30 M
Explanation:

According to the neutralization law,
where,
= molarity of
solution = ?
= volume of
solution = 24.6 ml
= molarity of
solution = 0.222 M
= volume of
solution = 33.0 ml
= valency of
= 21
= valency of
= 1
Therefore, the molarity of the HCI solution is 0.30 M
(a) 33.6 L of oxygen would be produced.
(b) 106 grams of
would be needed
<h3>Stoichiometric calculations</h3>
1 mole of gas = 22.4 L
(a) From the equation, 2 moles of
produce 3 moles of
. 1 mole of
will, therefore, produce 1.5 moles of
.
1.5 moles of oxygen = 22.4 x 1.5 = 33.6 L
(b) 22.4 L of
is produced at STP. This means that 1 mole of the gas is produced.
From the equation, 1 mole of
requires 1 mole of
.
Molar mass of
= (23x2)+ (12)+(16x3) = 106 g/mol
Mass of 1 mole
= 1 x 106 = 106 grams
More on stoichiometric calculations can be found here: brainly.com/question/27287858
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Answer : The percentage (by mass) of
in the mixture is 20 %
Explanation :
As we are given that, 10 % sulfur by mass that means 10 grams of sulfur present in 100 grams of mixture.
Mass of sulfur = 10 g
Mass of mixture = 100 g
Now we have to calculate the mass of
.
As, 32 grams of sulfur present in 64 grams of 
So, 10 grams of sulfur present in
grams of 
Thus, the mass of
is 20 grams.
Now we have to calculate the percentage (by mass) of
in the mixture.


Therefore, the percentage (by mass) of
in the mixture is 20 %