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Andrei [34K]
3 years ago
7

Help me please Look at the picture linked

Chemistry
1 answer:
____ [38]3 years ago
4 0

Halogen--Florine

Chalogen-- Oxygen

Alkali Metal-- Sodium

Boron -- Metalloid (atomic symbol B)

Lanthanide series-- (Number 57-71 on periodic Table) Example: Cerium #58

Alkaline Earth Metal--Magnesium

Transition Metal-- Gold, Iron, Silver. Etc... (Middle section of a period table)

Nobel Gas--Helium

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I’d appreciate the help! :)
seraphim [82]

Answer: 300g

Explanation:

first we write the given values on top

224L. x

3 NO2 (g) + H2O (l) = 2HNO3 (l) + NO (g)

22.4L 30g

then we form a formula

224L/22.4L= x/30g

224*30/22.4

6720/22.4= 300g

7 0
3 years ago
Help me please an thank you
agasfer [191]

Answer:

formula unit

Explanation:

3 0
3 years ago
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In a chemical equation, the sum of the masses ______.
Readme [11.4K]
C. Of the products is equal to the reactants.

Good luck out there! :)
5 0
3 years ago
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What would happen if there were not enough plants on earth
Sati [7]
Then we would not have oxygen because plants give oxygen in order to breathe
7 0
4 years ago
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Barium nitrate and sodium sulfate solutions can be used to precipitate barium sulfate. How many grams
-Dominant- [34]

Answer:

40.8g of sodium sulfate must be added

Explanation:

The reaction of barium nitrate, Ba(NO₃)₂ with sodium sulfate, Na₂SO₄ is:

Ba(NO₃)₂ + Na₂SO₄ → 2 NaNO₃ + BaSO₄(s)

That means, for a complete reaction of an amount of barium nitrate you must add the same amount in moles of sodium sulfate. To solve this problem we need to convert the mass of barium nitrate to moles = Moles of sodium sulfate that must be added:

<em>Moles Ba(NO₃)₂ -Molar mass: 261.3g/mol-:</em>

75g * (1mol / 261.3g) = 0.287 moles = Moles Na₂SO₄

<em>Mass Na₂SO₄ -Molar mass: 142.04g/mol-:</em>

0.287 moles * (142.04g / mol) =

<h3>40.8g of sodium sulfate must be added</h3>
7 0
3 years ago
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