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3 years ago

What is the solution of the following system -2x-y=1 -4x-2y=-1

Mathematics

2 answers:

motikmotik3 years ago

8 0

-2x - y = 1 (1st)

-4x - 2y = -1 (2nd)

Multiply 1st equation by 2

-4x - 2y = 2

Now you have 2 new equations

-4x - 2y = 2

-4x - 2y = -1

----------------------Subtract

0 ≠ 3

Answer: No solutions

andreev551 [17]3 years ago

7 0

Answer: The correct option is

(B) no solution.

Step-by-step explanation: We are given to find the solution to the following system of equations :

$-2x-y=1~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)\\\\-4x-2y=-1~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)$

From equation (i), we have

$-2x-y=1\\\\\Rightarrow y=-2x-1~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(iii)$

Substituting the value of y from equation (iii) in equation (ii), we get

$-4x-2(-2x-1)=-1\\\\\Rightarrow -4x+4x+2=-1\\\\\Rightarrow 2=-1,$

which can never be possible.

Therefore, the given system of equations has no solution.

Option (B) is CORRECT.

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Step-by-step explanation:

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2 years ago

g A program executes a mix of different instruction types. 25% of the instructions require two clock cycles to execute, 20% requ

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Answer:

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Step-by-step explanation:

The average number of clock cycles per instruction is given by the sum of the product of each possible number of cycles by its likelihood.

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$Avg = 0.5*1+0.25*2+0.20*3+0.05*4\\Avg= 1.8\ cycles$

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3 years ago

Arrange the slopes from flattest to steepest. -3/2, 0, 4/3, undefined

Dovator [93]

To arrange the slopes we need to take their absolute values.
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8 0

3 years ago

9x2 - 6xy Factorise Fully

tamaranim1 [39]

Remember distributive property, but reverse it
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4 0

3 years ago

Ivy is trying to manage the money she spends on lunch. Between eating out and buying groceries for bagged lunches, she wants to

mr_godi [17]

Answer:

The monetary choices for Ivy’s lunches is to spend less than $16.67 at restaurants and to spend less than $33.33 on groceries in order to to keep her weekly budget to less than $50.

Step-by-step explanation:

This can be determined as follows

x = the amount of dollars spent at restaurants

y = the amount of dollars spent on groceries

Since Ivy decides that she wants to spend at least twice as much on bagged lunches as at restaurants, we have

y = 2x .................. (1)

Since Ivy wants to keep her weekly budget to less than $50, using the x and y, we have:

x + 2x < 50 ............................ (2)

We can now solve for x as follows:

3x + < 50

x < 50 / 3

x < 16.67

Substituting the x < 17 into equation (1) noting that Ivy wants to keep her weekly budget to less than $50, we have:

y < 2 * 16.67

y < 33.33

Therefore, the monetary choices for Ivy’s lunches is to spend less than $16.67 at restaurants and to spend less than $33.33 on groceries in order to to keep her weekly budget to less than $50.

7 0

2 years ago