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Trava [24]
3 years ago
14

A linear function is parallel to the line y= 4x + 8 and also goes through the point (2,15).What is the linear equation for this

function?
Mathematics
1 answer:
horrorfan [7]3 years ago
3 0

When written in the y=mx+q form, the slope of a line is given by the coefficient m. Moreover, two lines are parallel if the have the same slope.


Now, the slope of the known line is 4, so our line's slope will be four as well.


In general, when you know the slope m of a line and one of its points (x_0,y_0), the equation of the line can be derived from the following formula:


y-y_0 = m(x-x_0)


Which in your case becomes


y-15 = 4(x-2)


Expand the right hand side and solve for y:


y = 4x+7

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Answer:

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Step-by-step explanation:

x | y

-------

1     5

5   10

9    15

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This one is linear because as x goes up by the same number so does y. So the ratio of difference of y to difference of x is the same per pair of points.

So a linear equation in slope-intercept form is y=mx+b where m is the slope and b is the y-intercept.

To find the slope, I'm going to line up the points vertically and subtract, then put 2nd difference over 1st difference. Like so,

( 1    ,   5)

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----------------

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So the slope is 5/4 which makes sense since the y's are going up by 5 each time and the x's are going up by 4 each time.

So we have m=5/4. Let's plug that into our y=mx+b.

y=5/4 x+b

To find b, we need to use y=5/4 x+b along with one of the given points.

Choose; it doesn't matter.  I like (1,5) I guess.

y=5/4 x +b with (1,5)

5=5/4 (1)+b

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15/4=b

The y-intercept is 15/4 so b=15/4.

So the equation for the line in slope-intercept form is y=5/4 x +15/4.

y=\frac{5}{4}x+\frac{15}{4}

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