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svet-max [94.6K]
3 years ago
12

Construct a Venn diagram for the following set

Mathematics
1 answer:
telo118 [61]3 years ago
4 0

Answer:

the picture is good

Step-by-step explanation:

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¿Cuál es la diferencia entre
Advocard [28]

Answer:

Can you do it in english? I can't read in spanish sorry.

4 0
2 years ago
If ADB = 70°,
Delvig [45]
Diameter of the circle is BD as shown, as indicated and passed through center where BD passes, triangle ABD is a right triangle with angle ABD as the right angle. It means ADB and ABD are complementary which means
AB = 140 degree
AD=40 degree
7 0
3 years ago
The distance Max's bike moves is directly proportional to how many rotations his bike's crank shaft has
Gemiola [76]

Answer:

187.5 feet

Step-by-step explanation:

we know that

Max's bike moves 25 feet after two rotations

so

using proportion

Find out how many feet will the bike move after 15 rotations

Let

x ----> the distance in feet

\frac{25}{2}\frac{ft}{rev}=\frac{x}{15}\frac{ft}{rev}\\\\x=15(25)/2\\\\x=187.5\ ft

7 0
3 years ago
Read 2 more answers
What is the nearest ten thousand of 85,001
Kipish [7]
The answer is 90,000. Just remember 5 or above, give it a shove, and for or below let it go. Because 85 has a five at the end you push it up to 90. Same thing with 85,000 or 85,001. You shove it to 90. If it was 84,000 or 84,999 you would let it go to 80,000. Hope that helped!
6 0
3 years ago
Read 2 more answers
What is the third quartile of this data set? <br> 20, 21, 24, 25, 28, 29, 35, 37, 42
nata0808 [166]

Answer:

36

Step-by-step explanation:

⇒The question is on third quartile

⇒To find the third quartile we calculate the median of the upper half of the data

Arrange the data in an increasing order

20, 21, 24, 25, 28, 29, 35, 37, 42

Locate the median, the center value

<u>20, 21, 24, 25</u>, 28, <u>29, 35, 37, 42</u>

<u />

The values 20, 21, 24, 25 ------------lower half used in finding first quartile Q1

The value 28 is the median

The vlaues 29, 35, 37, 42...............upper half used in finding 3rd quartile Q3

Finding third quartile Q3= median of the upper half

upper half= 29,35,37,42

median =( 35+37)/2 = 36

6 0
3 years ago
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