Answer: 13.5 hours.
I got the answer by simply adding up the integers to start with.
Integers = 1, 2, 3 and 5.
The integers added up equal to 11.
Next we add up the remaining fractions.
Fractions = 1/2, 3/4, 3/4 and 1/2.
We can add up 1/2 and 1/2 to equal 1, and 3/4 and 3/4 to make 1.5.
1 + 1.5 = 2.5
Finally, we add up the answer for the integers and the fractions together, (11 + 2.5) which equals 13.5.
Our answer is 13.5 hours.
(Not sure why the answer isn't in the choices)
Answer: 45b^4/32
Step-by-step explanation: First multiply the two fractions
15b^3y(3b)/8y x 4
Multiply 3 by 15
45b^3yb/8y x 4
Raise b to power of 1
45(b^1b^3)y/8y x 4
Use power rule to combine exponents
45b^1+3 y/8y x 4
Simplify
45b^4y/32y
Cancel common factor of y
45b^4/32
Answer:
The values of p in the equation are 0 and 6
Step-by-step explanation:
First, you have to make the denominators the same. to do that, first factor 2p^2-7p-4 = \left(2p+1\right)\left(p-4\right)2p
2
−7p−4=(2p+1)(p−4)
So then the equation looks like:
\frac{p}{2p+1}-\frac{2p^2+5}{(2p+1)(p-4)}=-\frac{5}{p-4}
2p+1
p
−
(2p+1)(p−4)
2p
2
+5
=−
p−4
5
To make the denominators equal, multiply 2p+1 with p-4 and p-4 with 2p+1:
\frac{p^2-4p}{(2p+1)(p-4)}-\frac{2p^2+5}{(2p+1)(p-4)}=-\frac{10p+5}{(p-4)(2p+1)}
(2p+1)(p−4)
p
2
−4p
−
(2p+1)(p−4)
2p
2
+5
=−
(p−4)(2p+1)
10p+5
Since, this has an equal sign we 'get rid of' or 'forget' the denominator and only solve the numerator.
(p^2-4p)-(2p^2+5)=-(10p+5)(p
2
−4p)−(2p
2
+5)=−(10p+5)
Now, solve like a normal equation. Solve (p^2-4p)-(2p^2+5)(p
2
−4p)−(2p
2
+5) first:
(p^2-4p)-(2p^2+5)=-p^2-4p-5(p
2
−4p)−(2p
2
+5)=−p
2
−4p−5
-p^2-4p-5=-10p+5−p
2
−4p−5=−10p+5
Combine like terms:
-p^2-4p+0=-10p−p
2
−4p+0=−10p
-p^2+6p=0−p
2
+6p=0
Factor:
p=0, p=6p
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