Write 19/25 as a decimal fist person to answer the question correctly is going to be the brainliest
2 answers:
You might be interested in
Given that,
The diameter of a semicircle is 2 mm.
To find,
The area of the semicircle.
Solution,
Radius of semicircle, r = 1 mm
The area of a semicircle is given by the formula as follow :
So, the area of the semicircle is .
Use graphs, and tables to find the limit, and identify any vertical asymptotes of the function. Limit of 1 divided by quantity x minus 10^2 as approaches 10 from the left.
The function f(x) = 1/(x - 10)
The table list values of f(x) for several x - values approaches 10 from left.
Observe Table, and Graph:
So, when X approaches 10 from the left (x - 10) is a small negative number. Thus, the quotient 1/(x - 10) is a large negative number and f(x) approaches negative infinity from the left side of the x = 10. Therefore, we can conclude that x = 10 is a Vertical Asymptote of the Graph of f(x) and lim x ----10 f(x) = lim x ---- 10 1/x - 10 = - infinity.
Check out upload, hope I was able to help you!!!
Hope that helps!!!
The function f(x) = 1/(x - 10)
The table list values of f(x) for several x - values approaches 10 from left.
Observe Table, and Graph:
So, when X approaches 10 from the left (x - 10) is a small negative number. Thus, the quotient 1/(x - 10) is a large negative number and f(x) approaches negative infinity from the left side of the x = 10. Therefore, we can conclude that x = 10 is a Vertical Asymptote of the Graph of f(x) and lim x ----10 f(x) = lim x ---- 10 1/x - 10 = - infinity.
Check out upload, hope I was able to help you!!!
Hope that helps!!!