What is the value of this expression?

At what values of x does the graph of f(x) = sin x intersect the x-axis?

kakasveta [241]

Step-by-step explanation:

$n\pi \ \\$

where n is an element of Integer

* the values of sinx intersects the x-axis when sinx=0

for example:

sin0°=sin180°=sin360°=0

4 0

4 years ago

436, 455, 280, 220, 353, 387, 119, 297, 241, 460, 393, 121, 146

Murrr4er [49]

First you would have to put the data in order.
119, 121, 146, 220, 241, 280, 297, 353, 387, 393, 436, 455, 460
To find the mean, you add up all the numbers and then divide by how many there are.
3908/13=300.6 (this is rounded to the nearest tenth)
To find the median, you have to look at the middle number
The median here is 297
To find the first quartile, you have to half the data set through the middle and find the middle number on the left
The first quartile is 220
Do the same thing for the third quartile, but look at the right data set
The third quartile is 393

Hope this helps!

4 0

4 years ago

Which of the following sets of sides does not form a right triangle?

kolezko [41]

Answer:

7, 24, 26

Step-by-step explanation:

6 squared is 36 and 8 squared is 64. Add them together and you get 100, which is 10 squared. Do the same for the other ones and you'll notice that 7 squared and 24 squared added together is 625, which is not 26 squared. In my head 25 squared is 625(check if you don't believe me) so I know that the answer is the third one. The basic formula for a right triangle is a^2 + b^2 = c^2, and that's how you find if three numbers form a right triangle or not. Hope this helps :)

3 0

3 years ago

Bennett has been practicing the cello for an hour each day. 3/4of the hour, he spends practicing musical pieces in preparation f

mina [271]

Answer:

$Orchestral\ Time = \frac{3}{10}\ hour$

Step-by-step explanation:

Given

$Time = 1\ hour$

$Musical\ Pieces = \frac{3}{4}\ hour$

$Practicing\ Sales = \frac{1}{4}\ hour$

Orchestral = $\frac{2}{5}$ of music practice time

Required

Determine time spent on orchestral pieces

From the given parameters, we have:

Orchestral = $\frac{2}{5}$ of music practice time

Substitute $\frac{3}{4}\ hour$ for music practice time.

So, we have:

$Orchestral\ Time = \frac{2}{5} * \frac{3}{4}\ hour$

$Orchestral\ Time = \frac{1}{5} * \frac{3}{2}\ hour$

$Orchestral\ Time = \frac{3}{10}\ hour$

7 0

4 years ago

Can someone solve this??

Dima020 [189]

Answer:

see below

Step-by-step explanation:

There are a few relevant relations involved:

an inscribed angle is half the measure of the arc it intercepts
an arc has the same measure as the central angle that intercepts it
the angle exterior to a circle where secants meet is half the difference of the intercepted arcs (near and far)
the angle interior to a circle where secants meet is half the sum of the intercepted arcs
the angle where tangents meet is the supplement of the (near) arc intercepted
an exterior angle of a triangle is equal to the sum of the remote interior angles
the angle between a tangent and a radius is 90°
the angle sum theorem

AB is a diameter, so arcs AB are 180°.

a) BC is the supplement to arc AC: 180° -140° = 40°

b) BG is the supplement to AG: 180° -64° -38° = 78°

c) ∠1 has the measure of BC: 40°

d) ∠2 is inscribed in a semicircle, so has measure 180°/2 = 90°

e) ∠3 is half the measure of arc AE: 64°/2 = 32°

f) ∠4 is half the sum of arcs AG and BC: ((64°+38°) +40°)/2 = 71°

g) ∠5 is half the difference of arcs AC and EG: (140° -38°)/2 = 51°

h) ∠6 is half the sum of arcs EAC and BG: ((140°+64°) +78°)/2 = 141°

i) ∠7 is the difference of exterior angle 4 and interior angle 1: 71° -40° = 31°

j) ∠8 is the measure of arc AC: 140°

k) ∠9 is the supplement to arc AC: 180° -140° = 40°

l) ∠10 is the complement of angle 7: 90° -31° = 59°

3 0

3 years ago