Answer:
f = 0.534×10⁻² Hz
Explanation:
Given data:
Frequency of wave= ?
Wavelength of wave = 5.62×10¹⁰ m
Solution:
Formula:
Speed of wave = wavelength × frequency
Speed of wave = 3×10¹⁷ nm/s
λ = 5.62×10¹⁰m×10⁹ nm/1 m = 5.62×10¹⁹ nm
Now we will put the values in formula.
3×10¹⁷ nm/s = 5.62×10¹⁹ nm × f
f = 3×10¹⁷ nm/s / 5.62×10¹⁹ nm
f = 0.534×10⁻² s⁻¹ or
f = 0.534×10⁻² Hz
Heat energy is absorbed by the substance.
a. 661.23 m/s
b. the rate of effusion of Ammonia = 4.5 faster than Silicon tetra bromide
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Further explanation
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Given
T = 25 + 273 = 298 K
Required
a. the gas speed
b. The rate of effusion comparison
Solution
a.
Average velocities of gases can be expressed as root-mean-square averages. (V rms)
R = gas constant, T = temperature, Mm = molar mass of the gas particles
From the question
R = 8,314 J / mol K
T = temperature
Mm = molar mass, kg / mol
Molar mass of Ammonia = 17 g/mol = 0.017 kg/mol
b. the effusion rates of two gases = the square root of the inverse of their molar masses:
M₁ = molar mass Ammonia NH₃= 17
M₂ = molar mass Silicon tetra bromide SiBr₄= 348
the rate of effusion of Ammonia = 4.5 faster than Silicon tetra bromide
You need to add the last substance to the products side(the right sode of the arrow). You have hydrogen and oxygen - water.
You get: BrO3 + N2H4 -> Br2 + N2 + H2O
# of Br: 1x1 = 1 # of Br: 2x1 = 2
O: 3x1 = 3 O: 1x1 = 1
N: 2x1 = 2 B N: 2x1 = 2
H: 4x1 = 4. H: 2x1 = 2
Br:
Multiply the reactant (left) side by 2 to balance.
O:
You've just multiplied the reactant oxygen by 2 so now the reactant side equals 6. Multiply the product (right) side by six as well.
H:
The product side is now equal to 12. Multiply the reactant side by 3 to balance.
N:
Now you have to balance N because the reactant side has been risen. So multiply the product side by three as well.
You end up with the complete and balanced equation:
2BrO3 + 3N2H4 -> Br2 + 3N2 + 6H2O
