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melisa1 [442]
3 years ago
12

How much of this reactant should he order to make

Chemistry
1 answer:
AlladinOne [14]3 years ago
4 0

Answer:

the answer is Fe2O3

Explanation:

The thermite reaction is described by the equation below: A welder has ... How much of this reactant should he order to make sure he runs out of both reactants at the same time? Round to the nearest hundredth and do not round any of your work until the very end. He should order Fe2O3 g of the limiting reactant.

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How many molecules are in 165 g of carbon dioxide?
Svet_ta [14]
М(СО₂)=165 г

н(СО₂)=м(углекислого газа)/М(СО₂)

Н=Nₐ*м(углекислого газа)/М(СО₂)

Н=6.022*1023 * 165/44.01=2.258*10²⁴
6 0
3 years ago
Read 2 more answers
Through what process do all stars produce their energy?
Deffense [45]

nuclear fusion

Stars produce their energy through nuclear fusion. For most stars, this process is dominated by a process called the "proton-proton chain," a sequence of events that transforms four hydrogen atoms into one helium atom.

5 0
2 years ago
When Mendeleev and other scientists arranged elements in order of increasing atomic mass, they noticed a repeating pattern of __
borishaifa [10]

The only answer that really makes sense here is the first one, properties. I would go with that one.

7 0
3 years ago
The balanced combustion reaction for C 6 H 6 C6H6 is 2 C 6 H 6 ( l ) + 15 O 2 ( g ) ⟶ 12 CO 2 ( g ) + 6 H 2 O ( l ) + 6542 kJ 2C
Lana71 [14]

Explanation:

First, we will calculate the molar mass of C_{6}H_{6} as follows.

Molar mass of C_{6}H_{6} = 6 \times 12 + 6 \times 1

                                   = 78 g/mol

So, when 2 mol of C_{2}H{6} burns, then heat produced = 6542 KJ

Hence, this means that 2 molecules of C_{6}H{6} are equal to 78 \times 2 = 156 g of C_{6}H_{6} burns, heat produced = 6542 KJ

Therefore, heat produced by burning 5.5 g of C_{6}H{6} =                  

       6542 kJ \times \frac{5.5 g}{156 g}

            = 228.97 kJ

            = 228970 J           (as 1 kJ = 1000 J)

It if given that for water, m = 5691 g

And, we know that specific heat capacity of water is 4.186 J/g^{o}C .

As,             Q = m \times C \times (T_{f} - T_{i})

          228970 J = 5691 g \times 4.184 J/g^{o}C \times (T_{f} - 21)
^{o}C

                T_{f} - 21^{o}C = 9.616^{o}C

                T_{f} = 30.6^{o}C

Thus, we can conclude that the final temperature of the water is 30.6^{o}C.

4 0
3 years ago
The systematic names for water, ammonia, and methane are dihydrogen monoxide, H2O; trihydrogen nitride, NH3; and tetrahydrogen c
Papessa [141]

Answer:

Most people, including chemists, prefer to use these common names for the compounds mentioned because they are frequently found, and the common names are shorter, easier to pronounce, and more widely known.

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4 years ago
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