Answer:
6.25 moles of N₂ is produced, and 18.8 moles of Cu and H₂O is produced.
Explanation:
We are given the chemical equation:

And we want to determine the amount of products produced when 12.5 moles of NH₃ is reacted with excess CuO.
Compute using stoichiometry. From the equation, we can see the following stoichiometric ratios:
- The ratio between NH₃ and N₂ is 2:1. (i.e. One mole of N₂ is produced from every two moles of NH₃.)
- The ratio between NH₃ and Cu is 2:3.
- The ratio between NH₃ and H₂O is 2:3. (i.e. Three moles of H₂O or Cu is produced frome every two moles of NH₃.)
Dimensional Analysis:
- The amount of N₂ produced:

- The amount of Cu produced:

- And the amount of H₂O produced:

In conclusion, 6.25 moles of N₂ is produced, and 18.8 moles of Cu and H₂O is produced.
D) Radioactive contamination
Answer:
i dont know what you're asking here. But if you're asking what it is then:
Explanation:
Aluminum Hydroxide + Hydrogen Chloride = Aluminum Chloride + Water
Al and Oh3: Aluminum Hydroxide
H and Cl: Hydrogen Chloride
Al and Cl3: Aluminum Chloride
H2O: water
btw the first letter of every element should be capitalized. While the second and theird are lowercased.