Hi there,
NH3 has the weight of 17.03 grams, and SF6 has the weight of 146.06 grams
so in total, there is 163.09 grams
Hope this helps :P
Answer:
2.90×10¯⁴M
Explanation:
Step 1:
Data obtained from the question.
Equilibrium constant for the acid , Ka = 3.5×10^–8
concentration of the acetic acid, [CH3COOH] = 2.40M
Concentration of Hydrogen ion, [H+] =..?
Step 2:
The balanced equation for the reaction.
CH3COOH(aq) <=> H+(aq) + CH3COO-(aq)
Step 3:
Determination of the concentration of Hydrogen ion, [H+]. This can be obtained as follow:
Initial concentration:
[CH3COOH] = 2.40M
[H+] = 0
[CH3COO-] = 0
During reaction:
[CH3COOH] = –y
[H+] = +y
[CH3COO-] = +y
At Equilibrium:
[CH3COOH] = 2.40 –y
[H+] = y
[CH3COO-] = y
Now, we can obtain the concentration of Hydrogen ion, H+ as follow:
Ka = [H+] • [CH3COO-] /[CH3COOH]
3.5×10^–8 = y×y/2.40
Cross multiply
y² = 3.5×10^–8 × 2.40
Take the square root of both side
y = √(3.5×10^–8 × 2.40)
y = 2.90×10¯⁴
[H+] = y = 2.90×10¯⁴M
Therefore, the concentration of H+ at equilibrium is 2.90×10¯⁴M
Formula units are another way of expressing "molecules". One mole is equivalent to .
Use dimensional analysis to solve this problem.
2.87 moles
Then, cross off the moles in the given number and the denominator, and your remaining unit is molecules of sodium carbonate.
Then, multiply and divide accordingly to the fraction.
2.87 * 6.022*10^23 = 1.72 * 10^24. Notice how the given problem has only 3 sig figs, so the answer should also have 3 sig figs
Your final answer would be 1.72 formula units of sodium carbonate.
The correct answer to the question above is heat. Most of the energy from a lower trophic level is converted into heat. When an organism from a higher trophic level consumed an organism from a lower trophic level, it is mostly heat that is being converted to.