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3 years ago

How many milliliters (ml) in this graduated cylinder?

Chemistry

1 answer:

Pavel [41]3 years ago

7 0

Answer:

9.4 mL.

Explanation:

To accurately determine the reading of the graduated cylinder, we simply take the reading under the curve (i.e meniscus)

From the above diagram, we can see that the reading under the curve is 9.4 mL.

Therefore, the reading of the cylinder is 9.4 mL

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Which of the following methods separates a homogeneous solution by spinning the solution very fast?

Zolol [24]

Answer:

The answer is (D) Magnetism

The methods separates a homogeneous solution by spinning the solution very fast is magnetism.

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3 years ago

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At 1000°C, cyclobutane (C4H8) decomposes in a first-order reaction, with the very high rate constant of 79 1/s, to two molecules

leva [86]

Explanation:

It is known that for first order reaction, the equation is as follows.

t = $\frac{2.303}{K} log \frac{[C_{4}H_{8}]_{o}}{[C_{4}H_{8}]_{t}}$

t = ?, K = rate constant = 79 1/s

Initial conc. of $C_{4}H_{8}$ = 1.68

Decompose amount of $C_{4}H_{8}$ = 52% of 1.68

= $\frac{52}{100} \times 1.68$

= 0.8736

= 0.87

Now, $[C_{4}H_{8}]_{t}$ = (1.68 - 0.87)

= 0.81

Therefore, calculate the value of t as follows.

t = $\frac{2.303}{K} log \frac{[C_{4}H_{8}]_{o}}{[C_{4}H_{8}]_{t}}$

= $\frac{2.303}{79 s^{-1}} log \frac{1.68}{0.81}$

= $\frac{2.303}{79 s^{-1}} \times 0.316$

= $9.212 \times 10^{-3}$ s

= $0.00921 s$

Thus, we can conclude that 0.00921 s will be taken for 52% of the cyclobutane to decompose.

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3 years ago

The invention of the _____________ was considered the critical invention for easily classifying and organizing Stars by brightne

kaheart [24]

Answer:

radio telescope

Explanation:

We use radio telescopes to study naturally occurring radio light from stars, galaxies, black holes, and other astronomical objects. We can also use them to transmit and reflect radio light off of planetary bodies in our solar system.

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3 years ago

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Name one chemical property of carbon disulfide

butalik [34]

One carbon and 2 sulfurs

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3 years ago

. The Henry's law constant for helium gas in water at 30 ∘C is 3.7×10−4M/atm; the constant for N2 at 30 ∘C is 6.0×10−4M/atm. a.

ludmilkaskok [199]

Explanation:

1) Henry's law states that the amount of gas dissolved or molar solubility of gas is directly proportional to the partial pressure of the liquid.

To calculate the molar solubility, we use the equation given by Henry's law, which is:

$M_{g}=K_H\times p_{g}$

where,

$K_H$ = Henry's constant

$p_{He}$ = partial pressure of gas

a) $K_H=3.7\times 10^{-4} M/atm$

$p_{He}=2.1 atm$

Putting values in above equation, we get:

$M_{He}=3.7\times 10^{-4} M/atm\times 2.1 atm = 7.77\times 10^{-4} M$

The solubility of helium gas is $7.77\times 10^{-4} M$

b) $K_H=6.0\times 10^{-4} M/atm$

$p_{N_2}=2.1 atm$

Putting values in above equation, we get:

$M_{He}=6.0\times 10^{-4} M/atm\times 2.1 atm = 1.26\times 10^{-3} M$

The solubility of nitrogen gas is $1.26\times 10^{-3} M$

a) Mass of solute or methanol , m= 14.7 g

Mass of solvent or water , m'= 186 g

Mass of the solution = M = m + m' = 14.7 g + 186 g = 200.7 g

$w/w\%=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 100$

$=\frac{14.7 g}{200.7 g}\times 100=7.32\%$

The mass percent of methanol is 7.32%.

b) Molality is defined as moles of solute per kilograms of solvent.

$m=\frac{\text{Moles of solute}}{\text{Mass of solvent in kg}}$

Moles of methanol = $\frac{14.7 g}{32 g/mol}=0.4594 mol$

Mass of solvent = 186 g = 0.186 kg

$m=\frac{0.4594 mol}{0.186 kg}=2.4610 mol/kg$

The molality of methanol is 2.4610 mol/kg.

4 0

3 years ago