Answer:
The mass of ice required to melt to lower the temperature of 353 mL of water from 26 ⁰C to 6 ⁰C is 85.4197 kg
Explanation:
Heat gain by ice = Heat lost by water
Thus,
Heat of fusion + 
Where, negative sign signifies heat loss
Or,
Heat of fusion + 
Heat of fusion = 334 J/g
Heat of fusion of ice with mass x = 334x J/g
For ice:
Mass = x g
Initial temperature = 0 °C
Final temperature = 6 °C
Specific heat of ice = 1.996 J/g°C
For water:
Volume = 353 mL
Density of water = 1.0 g/mL
So, mass of water = 353 g
Initial temperature = 26 °C
Final temperature = 6 °C
Specific heat of water = 4.186 J/g°C
So,


345.976x = 29553.16
x = 85.4197 kg
Thus,
<u>The mass of ice required to melt to lower the temperature of 353 mL of water from 26 ⁰C to 6 ⁰C is 85.4197 kg</u>
NaOH + HBr =⇒ NaBr + H2O
35.0 ml HBr x 1 liter/1000 mL x 0.140 moles HBr/ liter = 0.0049 moles HBr
0.0049 moles HBr x 1mole NaOH/1mole HBr = 0.0049 moles HBr
0.0049 moles HBr x 1 liter NaOH/0.200 moles NaOH x 1000 mL/1liter= 24.5 mL NaOH
Explanation:
The specially designed microwave units , for the synthesis , are often very expensive and at times get heated up .
The home microwave is suitable only in some case .
And , new modification done on the home microwave , increases the safety factor .
The chemical reactions which need to be done at very high pressure , are preferred to be carried in specially designed oven .
Hence ,
the home microwave is suitable only for some selected and specific reactions .
Answer:
All the options are correct except "has 7 electrons"
Explanation: