Answer:
.
Explanation:
Electrons are conserved in a chemical equation.
The superscript of
indicates that each of these ions carries a charge of
. That corresponds to the shortage of one electron for each
ion.
Similarly, the superscript
on each
ion indicates a shortage of three electrons per such ion.
Assume that the coefficient of
(among the reactants) is
, and that the coefficient of
(among the reactants) is
.
.
There would thus be
silver (
) atoms and
aluminum (
) atoms on either side of the equation. Hence, the coefficient for
and
would be
and
, respectively.
.
The
ions on the left-hand side of the equation would correspond to the shortage of
electrons. On the other hand, the
ions on the right-hand side of this equation would correspond to the shortage of
electrons.
Just like atoms, electrons are also conserved in a chemical reaction. Therefore, if the left-hand side has a shortage of
electrons, the right-hand side should also be
electrons short of being neutral. On the other hand, it is already shown that the right-hand side would have a shortage of
electrons. These two expressions should have the same value. Therefore,
.
The smallest integer
and
that could satisfy this relation are
and
. The equation becomes:
.
Answer:
The volume of the gas sample at standard pressure is <u>819.5ml</u>
Explanation:
Solution Given:
let volume be V and temperature be T and pressure be P.



1 torr= 1 mmhg
42.2 torr=42.2 mmhg
so,


Now
firstly we need to find the pressure due to gas along by subtracting the vapor pressure of water.

=735-42.2=692.8 mmhg
Now
By using combined gas law equation:



Here
are standard pressure and temperature respectively.
we have

Substituting value, we get


Mass of KNO₃ : = 40.643 g
<h3>Further explanation</h3>
Given
28.5 g of K₃PO₄
Required
Mass of KNO₃
Solution
Reaction(Balanced equation) :
2K₃PO₄ + 3 Ca(NO₃)₂ = Ca₃(PO₄)₂ + 6 KNO₃
mol K₃PO₄(MW=212,27 g/mol) :
= mass : MW
= 28.5 : 212,27 g/mol
= 0.134
Mol ratio of K₃PO₄ : KNO₃ = 2 : 6, so mol KNO₃ :
= 6/2 x mol K₃PO₄
= 6/2 x 0.134
= 0.402
Mass of KNO₃ :
= mol x MW KNO₃
= 0.402 x 101,1032 g/mol
= 40.643 g
Answer:
The Sigma (σ) Bond
S-S Overlapping. In this kind of overlapping, one 's' orbital from each participating atom undergoes head-on overlapping along the internuclear axis. ...
S-P Overlapping. ...
P-P overlapping.