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yawa3891 [41]
3 years ago
13

What is a group of electrons orbiting at roughly the same distance from the nucleus

Chemistry
1 answer:
Alex Ar [27]3 years ago
5 0
A shell of electrons.
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Ight I just here’s my first one
MatroZZZ [7]

Answer:

D

Explanation:

6 0
3 years ago
A certain first-order reaction 45% complete in 65seconds, determine the rate constant and the half life for the process ​
masha68 [24]

The rate constant : k = 9.2 x 10⁻³ s⁻¹

The half life : t1/2 = 75.3 s

<h3>Further explanation</h3>

Given

Reaction 45% complete in 65 s

Required

The rate constant and the half life

Solution

For first order ln[A]=−kt+ln[A]o

45% complete, 55% remains

A = 0.55

Ao = 1

Input the value :

ln A = -kt + ln Ao

ln 0.55 = -k.65 + ln 1

-0.598=-k.65

k = 9.2 x 10⁻³ s⁻¹

The half life :

t1/2 = (ln 2) / k

t1/2 = 0.693 : 9.2 x 10⁻³

t1/2 = 75.3 s

3 0
2 years ago
Why are gold and platinum sutible for making jewellery ? ​
Anon25 [30]

Answer:

Platinum Gold and silver are used to make jewellery because of the following reasons. They are highly lustrous metals which are resistant to corrosion. They are highly malleable and ductile so can be transformed into any shape or design.

Explanation:

6 0
2 years ago
Read 2 more answers
What steps should you take to respond to an accident?
Marina86 [1]
If it’s multiple answers then it’s A,C,D. If it’s only one answer then your best answer is A. Because you always report accidents to an authority so that they can figure out how to solve the problem.
5 0
2 years ago
Using the redox reaction below determine which element is oxidized and which is reduced. 4nh3 + 3ca(clo)2 → 2n2 + 6h2o + 3cacl2
lys-0071 [83]
The oxidation number of elements in equation below are,

                         4NH₃ + 3Ca(ClO)₂ → 2N₂ + 6H₂O + 3CaCl₂

O.N of N in NH₃ = -3
O.N of Ca in Ca(ClO)₂ and CaCl₂ = +2
O.N of N in N₂ = 0
O.N of Cl in Ca(ClO)₂ = +1
O.N of Cl in CaCl₂ = -1

Oxidation:
               Oxidation number of Nitrogen is increasing from -3 (NH₃) to 0 (N₂).

Reduction:
               Oxidation number of Cl is decreasing from +1 [Ca(ClO)₂] to -1 (CaCl₂).

Result:
          <span>N is oxidized and Cl is reduced.</span>
6 0
3 years ago
Read 2 more answers
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