The population will get low because the food we eat is animals which is species then the animals that eat that prey will die off because that might be there only prey....then if more species is gone there will be nothing left
I Hope this helped
Answer:
C₁₃H₁₈O₂
Explanation:
Empirical formula is the simplest ratio in moles of the elements presents in the compound. Assuming a basis of 100g, we need to convert the mass of each element to moles and, find the ratio of each of these:
<em>Moles C:</em>
75.69g * (1mol / 12.01g) = 6.3 moles of C
<em>Moles H:</em>
8.80g * (1mol / 1.01g) = 8.7 moles of H
<em>Moles O:</em>
15.51g * (1mol / 16g) = 0.97 moles of O
The ratio dividing in the moles of O -Because is the element with the lower amount of moles-:
C = 6.3mol / 0.97mol = 6.5
H = 8.7mol / 0.97mol = 9
O = 0.97mol / 0.97mol = 1
As the ratio must be in whole-numbers, multiplying in 2:
C = 13;
H = 18
O = 2
And empirical formula is:
<h3>C₁₃H₁₈O₂</h3>
Animals and plants use their cells by growing and observing food and oxygen
Answer:
92.93 g
Explanation:
Number of half lives that have elapsed in eight days =8/14.3 = 0.559
Fraction of the radioactive nuclide that remains after 0.559 half lives is given by
N/No=(1/2)^0.559
Where N= mass of radioactive nuclides remaining after a time t
No= mass of radioactive nuclides originally present
N/No=(1/2)^0.559= 0.679
Mass of nuclides present eight days before= 63.1g/0.679
Mass of nuclides present eight days before=92.93 g
