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3 years ago

A random number generator is used to create a list of 300 single-digit numbers. Of those 300 numbers, 146 are odd

Mathematics

2 answers:

expeople1 [14]3 years ago

8 0

I think it is 0.35 I hope this helps

faust18 [17]3 years ago

6 0

This is 0.35
…………………….

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A van travels 150 miles on 6 gallons of gas. How many gallons will it need to travel 325 miles?

diamong [38]

Answer:

C. 13 gallons

Step-by-step explanation:

150 divided by 6 is 25. 325 divided by 25 is 13.

8 0

3 years ago

A portion of the graph of f(x) = −x2 − 10x − 21 is shown. Which of the following describes all solutions for f(x)? a partial par

Ket [755]

Answer:

the answer is A

Step-by-step explanation:

you pluy in each number for the portion of the function in the graphing calculator and get the answer

7 0

3 years ago

Read 2 more answers

A geologist in South America discovers a

diamong [38]

Answer:

This is a radioactive decay / half-life problem.

Initial amount of C 14 = 100% Present Amount = 57%

k = .0001 (that value should be negative)

Nt = No * e^ (k*t)

You need to solve that equation for "time" (equation attached)

time = natural log (Ending amount / Starting Amount) / k

time = natural log (57% / 100%) / -.0001

time = ln (.57) / -.0001

time = -.56211891815 / -.0001

time = 5,621.2 years (age of the bird skeleton)

These problems are quite complicated but I think I know this pretty well.

Need to know more? Visit my website (it's on the graphic).

Step-by-step explanation:

7 0

3 years ago

HELP THIS IS DUE TODAY. A B C or D. The table shows the relationship of how many pounds of pecans are needed to make a certain n

vlabodo [156]

The 4th, did this and got a 100%

7 0

3 years ago

Solving separable differential equation DY over DX equals xy+3x-y-3/xy-2x+4y-8

Ivanshal [37]

It looks like the differential equation is

$\dfrac{dy}{dx} = \dfrac{xy + 3x - y - 3}{xy - 2x + 4y - 8}$

Factorize the right side by grouping.

$xy + 3x - y - 3 = x (y + 3) - (y + 3) = (x - 1) (y + 3)$

$xy - 2x + 4y - 8 = x (y - 2) + 4 (y - 2) = (x + 4) (y - 2)$

Now we can separate variables as

$\dfrac{dy}{dx} = \dfrac{(x-1)(y+3)}{(x+4)(y-2)} \implies \dfrac{y-2}{y+3} \, dy = \dfrac{x-1}{x+4} \, dx$

Integrate both sides.

$\displaystyle \int \frac{y-2}{y+3} \, dy = \int \frac{x-1}{x+4} \, dx$

$\displaystyle \int \left(1 - \frac5{y+3}\right) \, dy = \int \left(1 - \frac5{x + 4}\right) \, dx$

$\implies \boxed{y - 5 \ln|y + 3| = x - 5 \ln|x + 4| + C}$

You could go on to solve for $y$ explicitly as a function of $x$ , but that involves a special function called the "product logarithm" or "Lambert W" function, which is probably beyond your scope.

8 0

2 years ago