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fgiga [73]
2 years ago
6

A random number generator is used to create a list of 300 single-digit numbers. Of those 300 numbers, 146 are odd

Mathematics
2 answers:
expeople1 [14]2 years ago
8 0
I think it is 0.35 I hope this helps
faust18 [17]2 years ago
6 0
This is 0.35
…………………….
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A is (4,15) and b is (8,1) what is the midpoint of AB?
antoniya [11.8K]

Answer:

(6,8)

Step-by-step explanation:

midpoint=(x1+x2)÷2,(y1+y2)÷2

a(4,15) b(8,1)

x=4+8=12÷2=6

y=15+1=16÷2=8

Answer=(6,8)

8 0
2 years ago
14/7x8-35/7x2 help me simplify using order of operations
zlopas [31]
4116 first answer 7 times 8 subtract 35.Second multiply by 14.Lastly solve 7 times 2 and multiply it by what you got multiplying 14.
3 0
2 years ago
Assume that when adults with smartphones are randomly selected, 54% use them in meetings or classes (based on data from an lg sm
GuDViN [60]
Answer: 0.951%

Explanation:

Note that in the problem, the scenario is either the adult is using or not using smartphones. So, we have a yes or no scenario involved with the random variable, which is the number of adults using smartphones. Thus, the number of adults using smartphones follows the binomial distribution.

Let x be the number of adults using smartphones and n be the number of randomly selected adults. In Binomial distribution, the probability that there are k adults using smartphones is given by

P(x = k) = \frac{n!}{k!(n-k)!}p^k (1-p)^{n-k}

Where p = probability that an adult is using smartphones = 54% (since 54% of adults are using smartphones). 

Since n = 12 and k = 3, the probability that fewer than 3 are using smartphones is given by

P(x \ \textless \  3) = P(x = 0) + P(x = 1) + P(x = 2)
\\ \indent = \frac{12!}{0!(12-0)!}(0.54)^0 (1-0.54)^{12-0} + \frac{12!}{1!(12-1)!}(0.54)^1 (1-0.54)^{12-1} + \\ \indent \frac{12!}{2!(12-2)!}(0.54)^2 (1-0.54)^{12-2}
\\
\\ \indent = \frac{12!}{(1)(12!)}(0.46)^{12} + \frac{12(11!)}{(1)(11!)}(0.54)(0.46)^{11}+ \frac{12(11)(10!)}{(2)(10!)}(0.54)^2(0.46)^{10}
\\
\\ \indent = (1)(0.46)^{12} + (12)(0.54)(0.46)^{11}+ (66)(0.54)^2(0.46)^{10}
\\ \indent \boxed{P(x \ \textless \  3) \approx 0.00951836732 }


Therefore, the probability that there are fewer than 3 adults are using smartphone is 0.00951 or 0.951%.


5 0
3 years ago
The amount in a savings account increased from 200 to 216. What was the percent of increase?
aleksandrvk [35]
216/200=%
1.08 which equals 108%
4 0
3 years ago
The midpoint of gh is m(4,-3). One endpoint is G(-2,2). Find the coordinates of endpoint H
Mars2501 [29]

Answer:

Step-by-step explanation:

(-2 + x)/2= 4

-2 + x = 8

x = 10

(2 + y)/2 = -3

2 + y = -6

y = -8

(10, -8) for endpoint H

4 0
2 years ago
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