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3 years ago

10

Josie is training For a race. The ratio of the number of minutes She runs to the number of miles she runs in 20 to 3 she plans t

o run 10 miles. How many minutes will it take her

1 answer:

Hitman42 [59]3 years ago

8 0

It will take her about 67 minutes .. ( rounded )

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Given g(x)=8x+3 find the following g(-1) and g(2a+1)

Degger [83]

Answer:

g(-1) = -5

g(2a+1) = 16a+11

Step-by-step explanation:

Substitute the given value into the function and evaluate.

So for g(x) = 8x+3

You substitute g(-1)

So g(-1) = 8(-1)+3

That is how you get -5

Then g(2a+1)

So g(2a+1) = 8(2a+1)+3

Thats how you get 16a+11

Hope this helps. Mark as brainlist

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2 years ago

A parallelogram with sides s and t has perimeter 2s+2t. Kelly is decorating the edge of her parallelogram-shaped craft table. Th

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Answer:

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Step-by-step explanation:

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2 years ago

Which expression can be used to model the statement “On Wednesday, Nathaniel earned $10 less than he earned on Tuesday”?

oksian1 [2.3K]

Answer:

c. n-10

Step-by-step explanation:

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2 years ago

You are given the following equation.

saul85 [17]

Answer:

Step-by-step explanation:

Given the equation 4x²+ 49y² = 196

a) Differentiating implicitly with respect to y, we have;

$8x + 98y\frac{dy}{dx} = 0\\98y\frac{dy}{dx} = -8x\\49y\frac{dy}{dx} = -4x\\\frac{dy}{dx} = \frac{-4x}{49y}$

b) To solve the equation explicitly for y and differentiate to get dy/dx in terms of x,

First let is make y the subject of the formula from the equation;

If 4x²+ 49y² = 196

49y² = 196 - 4x²

$y^{2} = \frac{196}{49} - \frac{4x^{2} }{49} \\y = \sqrt{\frac{196}{49} - \frac{4x^{2} }{49} \\} \\$

Differentiating y with respect to x using the chain rule;

Let $u= \frac{196}{49} - \frac{4x^{2} }{49}$

$y = \sqrt{u} \\y =u^{1/2} \\$

$\frac{dy}{dx} = \frac{dy}{du} * \frac{du}{dx}$

$\frac{dy}{du} = \frac{1}{2}u^{-1/2} \\$

$\frac{du}{dx} = 0 - \frac{8x}{49} \\\frac{du}{dx} =\frac{-8x}{49} \\\frac{dy}{dx} = \frac{1}{2} ( \frac{196}{49} - \frac{4x^{2} }{49})^{-1/2} * \frac{-8x}{49}\\\frac{dy}{dx} = \frac{1}{2} ( \frac{196-4x^{2} }{49})^{-1/2} * \frac{-8x}{49}\\\frac{dy}{dx} = \frac{1}{2} ( \sqrt{ \frac{49}{196-4x^{2} })} * \frac{-8x}{49}\\\frac{dy}{dx} = \frac{1}{2} *{ \frac{7}\sqrt {196-4x^{2} }} * \frac{-8x}{49}\\$

$\frac{dy}{dx} = \frac{-4x}{7\sqrt{196-4x^{2} } }$

c) From the solution of the implicit differentiation in (a)

$\frac{dy}{dx} = \frac{-4x}{49y}$

Substituting $y = \sqrt{\frac{196}{49} - \frac{4x^{2} }{49} \\$ into the equation to confirm the answer of (b) can be shown as follows

$\frac{dy}{dx} = \frac{-4x}{49\sqrt{\frac{196-4x^{2} }{49} } }\\\frac{dy}{dx} = \frac{-4x}{49\sqrt{196-4x^{2}}/7} }\\\\\frac{dy}{dx} = \frac{-4x}{7\sqrt{196-4x^{2}}}$

This shows that the answer in a and b are consistent.

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3 years ago

A hardware store rent vacuum cleaners that customers for part or all of A day before returning. The Store charges a flat fee Plu

Pavel [41]

Answer:

Step-by-step explanation:

Let x represents the amount that the customer pays per hour

for renting the vacuum cleaner before returning it.

Let y represent the flat rate that the store charges a customer for renting the vacuum cleaner.

Let F represent the amount that the store charges a customer for renting the vacuum cleaner for x hours.

A linear function F for the total retail cost of a vacuum cleaner would be

F(x) = x + y

If the customer rents it for n hours, the total amount becomes

F(x) = nx + y

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2 years ago