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Mathematics

1 answer:

Viefleur [7K]3 years ago

8 0

Answer:

Step-by-step explanation:

the unit is 4 min and the answer is he can type 55 words in 1 min

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The sum of the number is 103.the second number is 4 times the third.the third number is 5 more then the first .what are the numb

Zigmanuir [339]

Answer:

13, 18, 72

Step-by-step explanation:

let x-5 represent the first number, since the first number is 5 less than the third number. let x represent the third number. let 4x represent the third number, since it's four times greater than the third number.

set up an equation, and make it equal to 103:

x-5+x+4x=103

solve:

6x-5=103

6x=108

x=18

so, the third number is 18.

the first number is equal to x-5, so:

18-5=13

the second number is equal to 4x, so:

4(18)=72

so, the three numbers are 13, 18, and 72.

4 0

2 years ago

<img src="https://tex.z-dn.net/?f=%5Csf%20-9%288-2h%29" id="TexFormula1" title="\sf -9(8-2h)" alt="\sf -9(8-2h)" align="absmiddl

coldgirl [10]

Answer:

$- 9(8 - 2h) \\ by \: distributive \: property \\ = - 9 \times 8 - ( - 9) \times ( - 2h) \\ = - 72 - 18h$

3 0

2 years ago

Read 2 more answers

(I've been trying to figure this out for 3 days and I really need help)

liq [111]

Check the picture below.

since the diameter of the cone is 6", then its radius is half that or 3", so getting the volume of only the cone, not the top.

$\bf \textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=3\\ h=4 \end{cases}\implies V=\cfrac{\pi (3)^2(4)}{3}\implies V=12\pi \implies V\approx 37.7$

now, the top of it, as you notice in the picture, is a semicircle, whose radius is the same as the cone's, 3.

$\bf \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=3 \end{cases}\implies V=\cfrac{4\pi (3)^3}{3}\implies V=36\pi \\\\\\ \stackrel{\textit{half of that for a semisphere}}{V=18\pi }\implies V\approx 56.55$

well, you'll be serving the cone and top combined, 12π + 18π = 30π or about 94.25 in³.

pretty much the same thing, we get the volume of the cone and its top, add them up.

$\bf \stackrel{\textit{cone's volume}}{\cfrac{\pi (3)^2(8)}{3}}~~~~+~~~~\stackrel{\stackrel{\textit{half a sphere}}{\textit{top's volume}}}{\cfrac{4\pi 3^3}{3}\div 2}\implies 24\pi +18\pi \implies 42\pi ~~\approx~~131.95~in^$