Answer:
a) X[bar]₁= 1839.20 cal
b) X[bar]₂= 1779.07 cal
c) S₁= 386.35 cal
Step-by-step explanation:
Hello!
You have two independent samples,
Sample 1: n₁= 15 children that did not eat fast food.
Sample 2: n₂= 15 children that ate fast food.
The study variables are:
X₁: Calorie consumption of a kid that does not eat fast food in one day.
X₂: Calorie consumprion of a kid that eats fast food in one day.
a)
The point estimate of the population mean is the sample mean
X[bar]₁= (∑X₁/n₁) = (27588/15)= 1839.20 cal
b)
X[bar]₂= (∑X₂/n₂)= (26686/15)= 1779.07 cal
c)
To calculate the sample standard deiation, you have to calculate the sample variance first:
S₁²=
[∑X₁² - (( ∑X₁)²/n₁)]=
= 149263.4571 cal²
S₁= 386.35 cal
I hope it helps!
I hope this helps
Answer:
32.75
Step-by-step explanation:
If you divide 131 by 4 (131/4), then you should get the answer 32.75, so if you need to round it, round it to 31, and if you do not need to round it, then it will be 32.75
Answer:
4
Step-by-step explanation:
Answer:
13 + 14 + 15
Step-by-step explanation:
n + (n + 1) + (n +2) =42
n + n + n + 1 + 2 = 42
3n + 3 = 42
(subtract 3 from both sides)
3n = 39
(divide both sides by 3)
n = 13
(solve)
n + (n + 1) + (n +2) =42
13 + (13 + 1) + (13 + 2) = 42
13 + (14) + (15) = 42
13, 14, 15
(Hope this helps, have a nice day!)