Question

Find 3 consecutive even integers such that 5 times the second is 82 more than the first .

Answer 1

Not 100% sure on this one.
Ti best of my understanding the answers are: 1st integers is 18, 2nd is 20, and 3rd is 22.
x is 1st integer
x+2 is 2nd integer
x+4 is 3rd integer
All even
5(x+2)=82+x
5x+10=82+x
5x-x=82-10
4x=72
x=18
1st is x=18
2nd is x+2=18+2=20
3rd is x+4=18+4=22
Good luck.