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Ksivusya [100]
3 years ago
13

Find 3 consecutive even integers such that 5 times the second is 82 more than the first .

Mathematics
1 answer:
Paraphin [41]3 years ago
6 0
Not 100% sure on this one.
Ti best of my understanding the answers are: 1st integers is 18, 2nd is 20, and 3rd is 22.
x is 1st integer
x+2 is 2nd integer
x+4 is 3rd integer
All even
5(x+2)=82+x
5x+10=82+x
5x-x=82-10
4x=72
x=18
1st is x=18
2nd is x+2=18+2=20
3rd is x+4=18+4=22
Good luck.
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Answer:

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Answer:

2\frac{2}{5}  + 2\frac{5}{8} \simeq 5

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Step-by-step explanation:

Mixed fraction a\frac{b}{c} can be converted into like or unlike fractions.

Here, a\frac{b}{c} =  \frac{ac +b}{b}

So, convert all the given fractions as follows:

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2\frac{2}{7} =  \frac{2(7) +2}{7} = \frac{16}{7}  =2.4

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2\frac{5}{8} =  \frac{2(8) +5}{8} = \frac{21}{8}  =2.6

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But an approximate sum of 5 is given by adding 2.4 + 2.6 = 5

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