Answer:
m∠CAO=8º
m∠SAC=82º
Step-by-step explanation:
We know that m∠OAS is 90º because it is a radius to a tangent. This will be useful later.
OA=OB because they are both radii. If we draw a line from A to B, this makes an isosceles triangle ABO with a vertex angle of 32 because of the central angle theorem. This means that m∠OAB and m∠OBA are both 74º.
Isosceles triangle CAB is also formed with the construction of AB. Using the inscribed angle theorem, we can find ACB, which is 16º. Solve for the other angles and you get 82º. To find m∠CAO, subtract m∠OAB from m∠CAB, and this returns 8.
To find m∠SAC, subtract m∠CAO from m∠OAS, which is 90º-8º, and you get 82º.
F(x) = -3 + 7 = 4
g(x) = -7 + 3 = -4
f(-3) - g(3) = 4 - (-4) = 4 + 4 = 8
Answer:
B
Step-by-step explanation:
To multiply scientific notation, multiply each part of the number.
(9 x 10)^2(2 x 10)^10 = (9*2) * (10^ 2 + 10) = 18 * 10 ^ 12
Since scientific notation can only have a digit in the ones place from 1-9. 18*10^12 becomes 1.8*10^13.
The solution is B.
Answer:
y = 9x-8
Step-by-step explanation:
Find y values for x= -3 and x = 3. These will come out to -35 and 19 respectively.
Plug these numbers into the rise/run equation for slope m (y2-y1)/ (x2-x1). Plugging values in and simplifying you will get 54/6, which reduces to 9. This is your m value.
Apply your m value to x = 3 going backwards (x = 2 gives a y value of 10, 1 gives 1, and 0 gives -8). This will give you a y intercept of -8. This is your b value.
Plug the slope and y intercept into the mx + b equation. This will give you y = 9x-8.
There you go!
