What kind of energy is required for photosynthesis to occur?

During one researcher's experiment, the total mass of the gas-generating solid and entire assembly was 52.1487g before the react

irinina [24]

Answer:

43.93 g/mol

Explanation:

The mass of the gas before reaction = 52.1487 g

The mass of the gas after reaction = 52.1098 g

Mass of gas generated = 0.0389 g

Moles of the gas = $8.854\times 10^{-4}\ moles$

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Molar\ mass = \frac{Mass\ taken}{Moles}$

$Molar\ mass= \frac{0.0389\ g}{8.854\times 10^{-4}\ moles}$

Molar mass of the gas = 43.93 g/mol

7 0

4 years ago

Practice Problem #1: __TiO2 + __Cl2 + __C __TiCl4 + __CO2 + __CO

ICE Princess25 [194]

Answer:

Explanation:

1)

Given data:

Moles of Cl₂ react = ?

Moles of carbon = 4.55 mol

Solution:

Chemical equation:

2TiO₂ + 4Cl₂ + 3C → 2TiCl₄ + CO₂ + 2CO

Now we will compare the moles of Cl₂ with C.

C : Cl₂

3 : 4

4.55 : 4/3×4.55 = 6.1 mol

6.1 moles of chlorine will react with 4.55 moles of C.

2)

Given data:

Mass of TiO₂ react = ?

Moles of carbon = 4.55 mol

Solution:

Chemical equation:

2TiO₂ + 4Cl₂ + 3C → 2TiCl₄ + CO₂ + 2CO

Now we will compare the moles of Cl₂ with C.

C : TiO₂

3 : 2

4.55 : 2/3×4.55 = 3 mol

Mass of TiO₂:

Mass = number of moles × molar mass

Mass = 3 mol × 79.87 g/mol

Mass = 239.61 g

3)

Given data:

Molecules of TiCl₄ formed = ?

Moles of TiO₂ react = 115 g

Solution:

Chemical equation:

2TiO₂ + 4Cl₂ + 3C → 2TiCl₄ + CO₂ + 2CO

Number of moles of TiO₂:

Number of moles = mass/ molar mass

Number of moles = 115 g/ 79.87 g/mol

Number of moles = 1.44 mol

Now we will compare the moles of Cl₂ with C.

TiO₂ : TiCl₄

2 : 2

1.44 : 1.44

Molecules of TiCl₄:

1 mole = 6.022 × 10²³ molecules

1.44 ×6.022 × 10²³ molecules

8.672× 10²³ molecules

8 0

4 years ago

A Pitot-static probe is used to measure the speed of an aircraft flying at 3000 m. If the differential pressure reading is 3100

inessss [21]

Answer:

82.59 m/s or 297.324 km/h

Explanation:

From the question,

Applying

V = √[2(P'/ρ)].................. Equation 1 ( From

Where V = Speed of the aircraft, Differential Pressure of the air craft, ρ = Density of air at an altitude of 3000 m.

Given: P' = 3100 N/m², ρ = 0.909 kg/m³

Substitute into equation 1

V = √[2(3100/0.909)]

V = √(2×3410.34)

V = √(6820.68)

V = 82.59 m/s

V = 297.324 km/h

Hence the speed of the aircraft is 82.59 m/s or 297.324 km/h

3 0

3 years ago

A mixture of gases with a pressure of 800.0 mm hg contains 60% nitrogen and 40% oxygen by volume. what is the partial pressure o

klasskru [66]

Hello!

We have the following statement data:

Data:
$P_{Total} = 800 mmHg$
$P\% N_{2} = 60\%$
$P\% O_{2} = 40\%$
$P_{partial} = ? (mmHg)$

As the percentage is the mole fraction multiplied by 100:

 $P = X_{ O_{2} }*100$

The mole fraction will be the percentage divided by 100, thus:
What is the partial pressure of oxygen in this mixture?

$X_{ O_{2} } = \frac{P}{100}$
$X_{ O_{2}} = \frac{40}{100}$
$\boxed{X_{ O_{2}} = 0.4}$

To calculate the partial pressure of the oxygen gas, it is enough to use the formula that involves the pressures (total and partial) and the fraction in quantity of matter:

In relation to $O_{2}$ :

$\frac{P O_{2} }{P_{total}} = X_O_{2}$
$\frac{P O_{2} }{800} = 0.4$
$P_O_{2} = 0.4*800$
$\boxed{\boxed{P_O_{2} = 320\:mmHg}}\end{array}}\qquad\quad\checkmark$

Answer:
b. 320.0 mm hg

7 0

3 years ago

What is the chemical composition of hot chocolate?

iris [78.8K]

Answer:

Hot chocolate is as straightforward as drinks go: at its core, it's milk, cocoa powder, and sugar. Despite its simplicity, this cold-weather classic is swirling with science. The backbone of any decent hot chocolate is milk. Beyond water, milk is perhaps the most basic and familiar substance to humans.

7 0

3 years ago