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1 year ago

the hemiacetal below is treated with 18o-labeled methanol (ch3o*h) and acid. where will the label appear in the products?

Chemistry

1 answer:

ioda1 year ago

8 0

The 18o-labeled methanol (CH3O*H) will appear in the products side at position b.

<h3>Position of 18o-labeled methanol in the products</h3>

The 18O label will appear at position b in the product as indicated in the image.

This methoxy group in the product formed in position b comes from the 18O-labeled methanol (CH3OH).

While the oxygens at positions a and c in the product come from the unlabeled hemiacetal.

Thus, the 18o-labeled methanol (CH3O*H) will appear in the products side at position b.

Learn more about methanol here: brainly.com/question/17048792
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c)KMnO₄

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1 mole of KMnO₄ contain 1 atom of K one atom of Mn and four atoms of O.

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6.022×10²³ × 6 atoms = 36.132 ×10²³ atoms

d) KCl

1 mole of KCl = 6.022×10²³ molecules

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