Answer:
3-³ x (1/3)^-5 x (1/3)-²
Applying Indices
3^-3 x (3-¹)^-5 x (3-¹)^-2
When the negative signs interact
they become positive
We now have
3^-3 x 3^5 x 3^2
= 3^-3 x 3^7
=3⁴.
Answer:
4.27 moles of NaCl
Explanation:
Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol
Number of moles of NaCl(table salt) = 250 grams /58.5 g/mol
= 4.27 moles of NaCl
Answer:
CH₅N
Explanation:
In the combustion, all of the C in the compound was used to produce CO₂ in a 1:1 ratio. Thus, the moles of CO₂ (MW 44.01 g/mol) produced equals the moles of C in the compound:
(44.0 g)(mol/44.01g) = 0.99977 mol CO₂ = 0.99977... mol C
Similarly, all of the H in the compound was used to produce H₂O in a ratio of 2H:1H₂O. The moles of H₂O (MW 18.02 g/mol) produced was:
(45.0 g)(mol/18.02g) = 2.497...mol H₂O
Moles of H is found using the molar ratio of 2H:1H₂O:
(2.497...mol H₂O)(2H/1H₂O) = 4.994...mol H
The ratio of H to C in the compound is:
(4.994...mol H)/(0.99977... mol C) = 5 H:C
Some NO₂ was produced from the N in the compound. Assuming a 1:1 ratio of C:N, the simplest empirical formula is: CH₅N.
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