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lidiya [134]
3 years ago
8

The activation energy for the reaction no2(g)+co(g)⟶no(g)+co2(g) is ea = 375 kj/mol and the change in enthalpy for the reaction

is δh = -225 kj/mol . what is the activation energy for the reverse reaction?
Chemistry
1 answer:
Georgia [21]3 years ago
3 0

Answer is: 600 kJ/mol.<span>
Chemical reaction: </span>NO₂(g) + CO(g) ⟶ NO(g) + CO₂(g).

<span> Ea(forward) = 375 kJ/mol.
Ea(reverse) = ? kJ/mol.
ΔH(reaction) = -225 kJ/mol; this is exothermic reaction.
The enthalpy change of reaction is the change in the energy of the reactants to the products.
ΔH(reaction) = Ea(forward) - Ea(reverse).
-225 kJ/mol = 375 kJ/mol - </span>Ea(reverse).
Ea(reverse)<span> = 600 kJ/mol.</span>

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According to the equation below, how many moles of PbO are required to generate 3.88×1023 nitrogen molecules?
saul85 [17]

Answer:

1.935 mole

Explanation:

We'll begin by calculating the number of mole present in 3.88x10^23 molecules of nitrogen(N2). This can be obtained as follow:

From Avogadro's hypothesis, 1 mole of any substance contains 6.02x10^23 molecules. Therefore 1 mole of N2 contains 6.02x10^23 molecules.

Now if 1 mole of N2 contains 6.02x10^23 molecules,

Then Xmol of N2 will contain 3.88x10^23 molecules i.e

Xmol of N2 = (3.88x10^23)/6.02x10^23

Xmol of N2 = 0.645 mole

Now, we can obtain the number of moles of PbO required to generate 3.88x10^23 molecules (i.e 0.645 mole) of N2. This is illustrated below:

The equation for the reaction is given below:

3PbO + 2NH3 → 3Pb + N2 + 3H2O

From the balanced equation above, 3 moles of PbO produced 1 mole of N2.

Therefore, Xmol of PbO will produce 0.645 mole of N2 i.e

Xmol of PbO = 3 x 0.645

Xmol of PbO = 1.935 mole.

From the calculations made above,

1.935 mole of PbO will produce 3.88x10^23 molecules of nitrogen (N2).

8 0
3 years ago
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zhuklara [117]

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2 years ago
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Particles of matter how have both potential and kinetic energy is that true or false?
guapka [62]
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5 0
3 years ago
it takes 513 kj to remove a mole of electrons from the atoms at the surface of a piece of metal. how much energy does it take to
schepotkina [342]

Answer:

The right solution is "8.5\times 10^{-19} \ joule".

Explanation:

As we know,

1 mole electron = 6.023\times 10^{23} \ no. \ of \ electrons

Total energy = 513 \ KJ

                     = 513\times 1000 \ joule

For single electron,

The amount of energy will be:

= \frac{513\times 1000}{(6.023\times 10^{23})}

= 8.5\times 10^{-19} \ joule

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