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lidiya [134]
3 years ago
8

The activation energy for the reaction no2(g)+co(g)⟶no(g)+co2(g) is ea = 375 kj/mol and the change in enthalpy for the reaction

is δh = -225 kj/mol . what is the activation energy for the reverse reaction?
Chemistry
1 answer:
Georgia [21]3 years ago
3 0

Answer is: 600 kJ/mol.<span>
Chemical reaction: </span>NO₂(g) + CO(g) ⟶ NO(g) + CO₂(g).

<span> Ea(forward) = 375 kJ/mol.
Ea(reverse) = ? kJ/mol.
ΔH(reaction) = -225 kJ/mol; this is exothermic reaction.
The enthalpy change of reaction is the change in the energy of the reactants to the products.
ΔH(reaction) = Ea(forward) - Ea(reverse).
-225 kJ/mol = 375 kJ/mol - </span>Ea(reverse).
Ea(reverse)<span> = 600 kJ/mol.</span>

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De acuerdo con la Ley de la Conservación de la Materia postulada por Lavoisier, ¿cuál ecuación química está balanceada? A C2H5OH
olya-2409 [2.1K]

Answer:

C C2H5OH(l) + 3O2(g) → 2CO2 + 3H2O

Explanation:

La ley de conservación de la materia implica que en una reacción química los átomos en los reactivos son iguales a la cantidad de átomos en los productos:

A C2H5OH(l) + O2(g) → CO2 + H2O

En los reactivos hay dos átomos de carbono pero en los productos solo 1. De esta manera, no cumple la ley de conservación.

B C2H5OH(l) + O2(g) → 2CO2 + H2O

En los reactivos hay 6 átomos de hidrógeno pero en los productos solo 2. No cumple la ley de conservación.

C C2H5OH(l) + 3O2(g) → 2CO2 + 3H2O

En los reactivos y productos hay: 2 átomos de carbono, 6 átomos de hidrógeno y 7 átomos de oxígeno. Cumple la ley de conservación.

D C2H5OH(l) + O2(g) → 2CO2 + 3H2O

En los reactivos hay 3 átomos de oxígeno y en los productos 7. No cumple la ley de conservación.

E 2C2H5OH(l) + 3O2(g) → 2CO2 + 3H2O

En los reactivos hay 4 átomos de carbono y en los productos solo dos. No cumple la ley de conservación.

6 0
3 years ago
Hydrogen gas, iodine vapor, hydrogen iodine are mixed in a flask and heated to 696°C. H2(g) + I2(g) ⇋ 2 HI(g) Kc = 52 at 696°C I
Anettt [7]

Answer: The equilibrium concentration of hydrogen gas is 0.0269 M

Explanation:

The chemical reaction follows the equation:

                  H_2(g)+I_2(g)\rightleftharpoons 2HI(g)

At t = 0          0.044M     0.044M              0.177M  

At t=t_{eq}    (0.044-x)M    (0.044-x)M      (0.177+x)M

The expression for K_c for the given reaction follows:

K_c=\frac{[HI]^2}{[H_2]\times [I_2]}

We are given:

K_c=52

Putting values in above equation, we get:

52=\frac{(0.177+x)^2}{(0.044-x)^2}

x=0.0171M

Hence, the equilibrium concentration of hydrogen gas is (0.044-x) M =(0.044-0.0171) M= 0.0269 M

7 0
3 years ago
Calculează masa zaharului si volumul apei necesare pentru prepararea 500g de soluție de zahăr cu partea de masa 20%
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m1 = solute 

m2 = Solvent

T = m1 / m1 + m2

0.2 = 500 g / 500 g + m2

0.2 * ( 500 + m2 ) = 500

0.2 * 500 + 0.2 m2 = 500

100 + 0.2 m2 = 500

0.2 m2 = 500 - 100

0.2 m2 = 400

m2 = 400 / 0.2

m2 = 2000 g of water

hope this helps!



7 0
3 years ago
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2. Mn is Oxidized

3. N is oxidized

Explanation:

<em>Check the image below:</em>

Reducing agent is an element or compound that loses an electron to an electron recipient in a redox chemical reaction. oxidizing agent is a substance that has the ability to oxidize other substances — in other words to accept their electrons.

6 0
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inna [77]

Answer:

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