I'd say B.) Increasing the voltage of the battery.
Answer:
KE = 1/2 * m * 
Explanation:
use the formula:
KE = 1/2 * m * 
KE = kinetic energy in joules (J)
m = mass in kg
v = velocity in m/s
Answer:
W = 1,307 10⁶ J
Explanation:
Work is the product of force by distance, in this case it is the force of gravitational attraction between the moon (M) and the capsule (m₁)
F = G m₁ M / r²
W = ∫ F. dr
W = G m₁ M ∫ dr / r²
we integrate
W = G m₁ M (-1 / r)
We evaluate between the limits, lower r = R_ Moon and r = ∞
W = -G m₁ M (1 /∞ - 1 / R_moon)
W = G m1 M / r_moon
Body weight is
W = mg
m = W / g
The mass is constant, so we can find it with the initial data
For the capsule
m = 1000/32 = 165 / g_moon
g_moom = 165 32/1000
.g_moon = 5.28 ft / s²
I think it is easier to follow the exercise in SI system
W_capsule = 1000 pound (1 kg / 2.20 pounds)
W_capsule = 454 N
W = m_capsule g
m_capsule = W / g
m = 454 /9.8
m_capsule = 46,327 kg
Let's calculate
W = 6.67 10⁻¹¹ 46,327 7.36 10²² / 1.74 10⁶
W = 1,307 10⁶ J
Whan object is at equilibrium, then the forces are balanced. Balanced is the key word that is used to describe equilibrium situations.
Answer:
Weight=686.7N,
, S.G.=0.933, F=17.5N
Explanation:
So, the first value the problem is asking us for is the weight of methanol. (This is supposing there is a mass of methanol of 70kg inside the tank). We can find this by using the formula:
W=mg
so we can substitute the data the problem provided us with to get:

which yields:
W=686.7N
Next, we need to find the density of methanol, which can be found by using the following formula:

we know the volume of methanol is 75L, so we can convert that to
like this:

so we can now use the density formula to find our the methanol's density, so we get:



Next, we can us these values to find the specific gravity of methanol by using the formula:

when substituting the known values we get:

so:
S.G.=0.933
We can now find the force it takes to accelerate this tank linearly at 
F=ma

F=17.5N