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3 years ago

Someone please help I dont understand. Will mark brainliest!!!!

Mathematics

2 answers:

Juli2301 [7.4K]3 years ago

7 0

Answer:

Is there a choices?

Step-by-step explanation:

Art [367]3 years ago

6 0

The answer may be 48

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5/6 + 5/6 how do you simplify the answer

aev [14]

Do a t chart with the factors and then add the greatest common factor (GCF) with the fraction

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3 years ago

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A taxi is charging you $1.50 per 500 meters. If you know your destination is 7.1 miles away, how much will the taxi cost you? Th

Anuta_ua [19.1K]

Answer:

$34.27

Step-by-step explanation:

First, we should make everything the same value, so convert the 7.1 miles into meters. (11,423.9 meters). Since we are trying to find a value <em>per</em> 500 meters, divide the 11,423.9 meters by 500 to get 22.8478. Multiply this number by $1.50 to get the value 34.2717 and since we are rounding to the cent, that would be $34.27

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3 years ago

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Pregnant women metabolize some drugs at a slower rate than the rest of the population. The half-life of caffeine is about 4 hour

UkoKoshka [18]

Answer:

Husband:

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Woman:

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

Step-by-step explanation:

The amount of caffeine in the body can be modeled by the following equation:

$C(t) = C(0)e^{rt}$

In which C(t) is the amount of caffeine t hours after 8 am, C(0) is how much coffee they took and r is the rate the the amount of caffeine decreases in their bodies.

110 mg of caffeine at 8 am,

So $C(0) = 110$

Husband

Half life of 4 hours. So

$C(4) = 0.5C(0) = 0.5*110 = 55$

$C(t) = C(0)e^{rt}$

$55 = 110e^{4r}$

$e^{4r} = 0.5$

Applying ln to both sides

$\ln{e^{4r}} = \ln{0.5}$

$4r = \ln{0.5}$

$r = \frac{\ln{0.5}}{4}$

$r = -0.1733$

So for the husband

$C(t) = 110e^{-0.1733t}$

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

$C(t) = 110e^{-0.1733t}$

$C(11) = 110e^{-0.1733*11} = 16.35$

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Pregnant woman

Half life of 10 hours. So

$C(10) = 0.5C(0) = 0.5*110 = 55$

$C(t) = C(0)e^{rt}$

$55 = 110e^{10}$

$e^{10r} = 0.5$

Applying ln to both sides

$\ln{e^{10r}} = \ln{0.5}$

$10r = \ln{0.5}$

$r = \frac{\ln{0.5}}{10}$

$r = -0.0693$

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

$C(t) = 110e^{-0.0693t}$

$C(11) = 110e^{-0.0693*11} = 51.33$

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

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3 years ago

Which of the following are solutions to the equation below? check all that apply. 9x^2-6x+1=7

Evgesh-ka [11]

The answer is C and D

First we must make one side of the equation zero, so we subtract 7 on both sides of the equation, making the equation <span>9x^2 - 6x - 6 = 0

Then we will use the quadratic formula to find the answers.

</span>using the Quadratic Formula where:
a = 9, b = -6, and c = -6

and the formula is 6 +- $\sqrt{6^2 - 4(9)(-6)}$ / 2(9)

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3 years ago

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HOW CAN ARITHMETIC AND GEOMETRIC SEQUENCES BECOME LINEAR AND EXPONENTIAL FUNCTIONS?

vladimir1956 [14]

A sequence is a set of numbers, called terms, arranged in some particular order. An arithmetic sequence is a sequence with the difference between two consecutive terms constant. The difference is called the common difference. A geometric sequence is a sequence with the ratio between two consecutive terms constant.

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