X is directly proportional with the square root of Y. If X=128 and Y=16 find: X when Y=36 B) Y when X=48 ( HELP ASAP!)
1 answer:
x = sqrt{y}k
K is the constant of proportionality.
128 = sqrt{16}k
128 = 4k
128/4 = k
32 = k
x = sqrt{y}k
x = sqrt{36}•32
x = 6 • 32
x = 192
Find y when x = 48.
x = sqrt{y}k
48 = sqrt{y}32
48/32 = sqrt{y}
(48/32)^2 = [sqrt{y}]^2
2.25 = y
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