Answer:
The unit vector u is (-5/√29) i - (2/√29) j
Step-by-step explanation:
* Lets revise the meaning of unit vector
- The unit vector is the vector ÷ the magnitude of the vector
- If the vector w = xi + yj
- Its magnitude IwI = √(x² + y²) ⇒ the length of the vector w
- The unit vector u in the direction of w is u = w/IwI
- The unit vector u = (xi + yj)/√(x² + y²)
- The unit vector u = [x/√(x² + y²)] i + [y/√(x² + y²)] j
* Now lets solve the problem
∵ v = -5i - 2j
∴ IvI = √[(-5)² +(-2)²] = √[25 + 4] = √29
- The unit vector u = v/IvI
∴ u = (-5i - 2j)/√29 ⇒ spilt the terms
∴ u = (-5/√29) i - (2/√29) j
* The unit vector u is (-5/√29) i - (2/√29) j
We can use the Pythagorean theorum
a^2+b^2=c^2
c^2 is the length of the longest side squared
so
6^2 + b^2 = 10^2
36+ b^2 = 100
-36 -36
b^2 = 64
b = 8
b is the same thing as your "x", so x = 8
Answer:
15.8 in.
Step-by-step explanation:
63.2 / 4 = 15.8
Answer:
A. (–8, 2)
Step-by-step explanation:
(1) y = ½x + 6
(2) y = -¾x – 4 Set (1) = (2)
½x + 6 = -¾x – 4 Multiply each side by 4
2x + 24 = -3x – 16 Add 16 to each side
2x + 40 = -3x Subtract 2x from each side
40 = -5x Divide each side by -5
(3) x = -8 Substitute (2) into (1)
y = ½(-8) +6
= -4 + 6
= 2
The solution to the system of equations is (-8 ,2).
You can see the graphs of the two functions in the figure below. The two lines intersect at (-8, 2).
Check:
2 = ½(-8) + 6 2 = -¾(-8) - 4
2 = -4 +6 2 = 6 - 4
2 = 2 2 = 2
