Question

X is directly proportional with the square root of Y. If X=128 and Y=16 find: X when Y=36 B) Y when X=48 ( HELP ASAP!)

Answer 1

x = sqrt{y}k

K is the constant of proportionality.

128 = sqrt{16}k

128 = 4k

128/4 = k

32 = k

x = sqrt{y}k

x = sqrt{36}•32

x = 6 • 32

x = 192

Find y when x = 48.

x = sqrt{y}k

48 = sqrt{y}32

48/32 = sqrt{y}

(48/32)^2 = [sqrt{y}]^2

2.25 = y