Given functions are


The total number of ducks and swans in the lake after n months can be determined by adding the functions s(n) and d(n).





Taking 2 as common, we get
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Hence The total number of ducks and swans in the lake after n months is
Answer:
56,149 would be left over
Step-by-step explanation:
56,941-792=56,149
Answer:
Blank 1: (-7,0)
Blank 2: (-1,0)
Step-by-step explanation:
Plug x=0 into the equation and solve the resulting equation y=7 for y
Plug y=0 into the equation and solve the resulting equation 0=(x+1)(x+7) for x
Answer: 4.8 ounces
Step-by-step explanation:
In total there are 12 ounces. If she drinks 3/5 of 12 you multiply 3/5 by 12.
3/5 * 12 would be equal to 3/5 * 12/1 which is 36/5. You have found how much she has drank. 36/5 is also equal to 7.2 ounces. Subtract 7.2 form 12 and you get 4.8 ounces.
Hope this helped!
Let us say ,
x=number of students who passed
y=number of students who failed
total number of students =276
x+y=276..................(1)
We are given 5 times the number of students passed as failed.
x=5y.............(2)
plugging value of x from (2) in (1),
5y+y=276
6y=276
y=46
x=5y=46*5=230
x=number of students who passed=230